 | Levi Leonard Conant - Trigonometry - 1909 - 320 pages
...the opposite parts. Napier's rules for the solution of spherical right triangles are as follows : 1. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 2. The sine of the middle part is equal to the product of the cosines... | |
 | Arthur Graham Hall, Fred Goodrich Frink - Trigonometry - 1910 - 204 pages
...The sine of the middle part is equal to the product of the tangents of the two adjacent parts ; II. The sine of the middle part is equal to the product of the cosines of the two opposite parts. The alliterative element in the device is obvious. The validity of the rules appears... | |
 | Alfred Monroe Kenyon, Louis Ingold - Trigonometry - 1913 - 300 pages
...adjacent or both opposite. Napier's rules refer to these circular parts and are as follows : EULE 1. The sine of the middle part is equal to the product of the cosines of the opposite parts. RULE 2. The sine of the middle part is equal to the product of the tangents of the adjacent parts.... | |
 | Robert Édouard Moritz - Trigonometry - 1913 - 562 pages
...c, are called opposite parts. Then each of the five equations on the right are contained in Rule 1. The sine of the middle part is equal to the product of the tangents of the adjacent parts, and the five on the left are contained in Rule 2. The sine of the middle... | |
 | Alfred Monroe Kenyon, Louis Ingold - Trigonometry - 1913 - 184 pages
...1. The sine of the middle part is equal to the product of the cosines of the opposite parts. BULE 2. The sine of the middle part is equal to the product of the tangents of the adjacent parts. These rules may be remembered by the alliteration of the first vowel... | |
 | George Neander Bauer, William Ellsworth Brooke - Trigonometry - 1917 - 196 pages
...follows : The sine of the middle part is equal to the product of the cosines of the opposite parts. The sine of the middle part is equal to the product of the tangents of the adjacent parts.* * To associate cosine with opposite and tangent with adjacent, it... | |
 | George Neander Bauer, William Ellsworth Brooke - Trigonometry - 1917 - 344 pages
...follows : The sine of the middle part is equal to the product of the cosines of the opposite parts. Tlie sine of the middle part is equal to the product of the tangents of the adjacent parts.* * To associate cosine with opposite, and tangent with adjacent, it... | |
 | James Atkins Bullard, Arthur Kiernan - Trigonometry - 1922 - 252 pages
...obtained from the following rules given by Napier: In a right spherical triangle, 1. The sine of a middle part is equal to the product of the cosines of the opposite parts. 2. The sine of a middle part is equal to the product of the tangents of the adjacent parts. (61) The... | |
 | Science - 1922 - 414 pages
...Rules: The five parts are a, b, с0 с, с0 а, с0 ß, where с0 с = c. The right angle 7 is omitted. The sine of the middle part is equal to the product of the tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
