 | Benjamin Peirce - Plane trigonometry - 1845 - 498 pages
...other two parts are called the opposite parts. The two theorems are as follows. Napier's Rules. II. The sine of the middle part is equal to the product of the cosines of the two opposite parts. [B. p. 436.] Proof. To demonstrate the preceding rules, it is only necessary to... | |
 | Charles Davies - Trigonometry - 1849 - 372 pages
...circular parts, as already defined. 1st. Radius into the sine of the middle part is equal to the rectangle of the tangents of the adjacent parts. 2d. Radius into the sine of the middle part is equal to the rectangle of the cosines of the opposite parts. These rules are proved by assuming each of the five... | |
 | James Hann - Spherical trigonometry - 1849 - 84 pages
...two are called extremes disjunct*. These things being understood, the following is the general rule. The sine of the middle part is equal to the product of the tangents of the extremes conjunct. * Thus, if in figure page 12 we suppose В С, the angle B, and... | |
 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...circular parts, .as. already defined. 1st. Radius into the sine of % middle part is equal to toe rectangle of the tangents of the adjacent :parts. 2d. Radius into the sine of the middle part is equal to the rectangle of the cosines of the opposite parts. ered, take that one of the general equations for obliqueangled... | |
 | Benjamin Peirce - Trigonometry - 1852 - 410 pages
...sine of the middle part is equal to the product of the tangents of the two adjacent parts. IL TJie sine of the middle part is equal to the product of the cosines of the two opposite parts. [B. p. 436.] Proof. To demonstrate the preceding rules, it is only necessary to... | |
 | Benjamin Peirce - Trigonometry - 1852 - 382 pages
...parts ; and the other two parts are called the opposite parts. The two theorems are as follows. I. The sine of the middle part is equal to the product of the tangents of the two adjacent parts. II. The sine of the middle part is equal to the product of the... | |
 | William Chauvenet - 1852 - 268 pages
...angle not being considered, the two sides including it are regarded as adjacent. The rules are : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...circular parts, as already defined. 1st. Radius inlo the sine of the middle part is equal to the rectangle of the tangents of the adjacent parts. 2d. Radius into the sine of the middle part is equal to the tidangle of the cosines of the opposite parts. These theorems are proved by assuming each of the five... | |
 | Elias Loomis - Trigonometry - 1855 - 192 pages
...part required may then be found by the following RULE OF NAPIER. (211.) The product of the radius and the sine of the middle part, is equal to the product of the tangents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist... | |
 | Charles Davies, William Guy Peck - Mathematics - 1855 - 628 pages
...middle pari is equal to the products of the tangents of the adjacent parís. 2. The tine of the muidle part is equal to the -product of the cosines of the opposite part* : thus, sin (90° - «) = tan (90° - B) tan (90° - C), and sin (90° — it) = cos e cos 4.... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
