 | Benjamin Greenleaf - Arithmetic - 1844 - 208 pages
...for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | Arithmetic - 1845 - 210 pages
...contained in the left hand period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try how often this divisor (with the figure used in... | |
 | Arithmetic - 1845 - 196 pages
...root. 2. Find the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first! figure in the next period for a dividend. 3. Involve the root to the next inferior power to... | |
 | Horatio Nelson Robinson - Arithmetic - 1845 - 310 pages
...power. 2.' Find the first figure of the root by the table of powers, or by trial; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that... | |
 | Almon Ticknor - Arithmetic - 1846 - 276 pages
...hand period, and place <he root to the right of the given number, and subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Square the root, and multiply it by three for a defective divisor. 4. Reserve mentally the units... | |
 | Benjamin Peirce - Algebra - 1855 - 308 pages
...and its root is the left hand figure of the required root. Subtract the square of the root thus found from the left hand period, and to the remainder bring down the second period "for a dividend. Double the root for a divisor, and the quotient of the dividend exclusive... | |
 | Dana Pond Colburn - Arithmetic - 1856 - 392 pages
...left hand period, and place its root as the first figure of the required root. Third. Subtract this cube from the left hand period, and to the remainder bring down the next period, calling the result a dividend. Fourth. Find three times the square of the part of the root already... | |
 | Roswell Chamberlain Smith - Arithmetic - 1856 - 334 pages
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,... | |
 | Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the, quotient by... | |
 | Joseph Ray - Arithmetic - 1857 - 348 pages
...its root on the right. like a quotient in division. Subtract the square of this root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the .root found, and place it on the left for a trial divisor. Find how many times the divisor... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend... 
