 | James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...not too great, of the first period, for the first figure of your root, subtract its cube from said period, and to the remainder bring down the next period for a resolvend. Take three times the square of the root for a defective divisor, and seek how often it is... | |
 | Stephen Pike - Arithmetic - 1835 - 210 pages
...root. 2. lind the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that... | |
 | Silas Totten - Algebra - 1836 - 360 pages
...the right, after the manner of a quotient in division. !Sid,tract its cube from the aforementioned period, and to the remainder bring down the next period for a dividend. for a divisor. Seek how often the divisor is contained in the dividend, and place the result in the... | |
 | Mathematics - 1836 - 488 pages
...subtract from the highest period the greatest square contained in it, place the root in the quotient, and to the remainder bring down the next period for a dividend. 2. Double the root already found, (understanding a cypher at the right,) for a divisor, and divide... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...for the first figure of the root, and the square itself under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and annex a cipher to tho product, for a divisior. Seek how many... | |
 | Daniel Adams - Arithmetic - 1837 - 274 pages
...number in the left hand period, and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor; seek how many times the divisor is contained in the... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...the left hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30,... | |
 | Benjamin Peirce - Algebra - 1837 - 302 pages
...and its root is the left hand figure of the required root. Subtract the square of the root thus found from the left hand period, and to the remainder bring down the second period for a dividend. Square Root of Numbers. Double the root for a divisor, and the quotient... | |
 | Luther Ainsworth - Arithmetic - 1837 - 298 pages
...for the first figure of the root, and place the cube under the first period, subtract it therefrom, and to the remainder, bring down the next period for a dividend. Q. You have now found one figure of the root, what is your next process ? A. Multiply the square of... | |
 | Zadock Thompson - Arithmetic - 1838 - 174 pages
...three figures each, find the greatest cube in the left hand period, and place its root in the quotient Subtract the cube from the left hand period, and to the remainder bring down the next pariod for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend... 
