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" ... for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. "
A Treatise on Plane and Spherical Trigonometry: With Their Most Useful ... - Page 6
by John Bonnycastle - 1806 - 419 pages
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The Last Words of Thomas Carlyle

Thomas Carlyle - Authors, Scottish - 1892 - 416 pages
...easy and certain as a question in the Rule of Three. Multiply the second and third terms toge flier, and divide the product by the first, and the quotient will be the answer ! Trust me, friend, before you come to my time of day, you will find there is a devilish fraction...
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Sartor Resartus

Thomas Carlyle - 1896 - 522 pages
...to that, and the whole problem of existence is easy and certain as a question in the Rule of Three: Multiply the second and third terms together, and...product by the first, and, the quotient will be the answer. Trust me, friend, before you come to my time of day, you will find there is a devilish fraction...
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Sartor Resartus

Thomas Carlyle - Clothing and dress - 1897 - 508 pages
...to that, and the whole problem of existence is easy and certain as a question in the Rule of Three : Multiply the second and third terms together, and...product by the first, and the quotient will be the answer. Trust me, friend, before you come to my time of day, you will find there is a devilish fraction...
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Aids to Engineers' Examinations: Prepared for Applicants of All Grades, with ...

Nehemiah Hawkins - Steam engineering - 1898 - 230 pages
...of the two remaining numbers for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. NOTE.— If the first...
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Hand Book of Calculations for Engineers and Firemen: Relating to the Steam ...

Nehemiah Hawkins - Steam engineering - 1901 - 354 pages
...les the two remaining numbers for the second term, and tin. greater for the Arst; and in either case multiply the second and third terms together, and divide the product by the first for the answer., which will always be of the same denomination as the third term. NOTE. If the first...
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Development of Arithmetic as a School Subject ...

Walter Scott Monroe - Arithmetic - 1917 - 180 pages
...quality with the answer required, the second term. 2. Multiply the second and third numbers together, divide the product by the first, and the quotient will be the answer to the question, which (as also the remainder) will be in the same denomination you left the...
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Audels New Marine Engineers Guide: A Practical Treatise on Marine Engines ...

Theodore Lucas, Frank Duncan Graham, Nehemiah Hawkins - Marine engineering - 1918 - 940 pages
...of the two remaining numbers for the second term and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. EXAMPLE. If 40 tons...
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The Elementary School Teacher's Uses of Educational Tests

Thomas George Foran - Educational tests and measurements - 1925 - 358 pages
...quality with the answer required, the second term. 2. Multiply the second and the third numbers together; divide the product by the first, and the quotient will be the answer to the question, which (as also the remainder) will be in the same denomination you left the...
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Bulletin, Issues 1-11

Education - 1917 - 904 pages
...quality with the answer required, the second term. 2. Multiply the second and third numbers together, divide the product by the first, and the quotient will be the answer to the question, which (as also the remainder) will be in the same denomination you left the...
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The Imperial Magazine, Or, Compendium of Religious, Moral ..., Volume 2

1820 - 618 pages
...necessary, to the same denomination, and the third to the lowest denomination mentioned in it. 4. Then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer in the same denomination as that to which the third term...
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