 | James Bates Thomson - Arithmetic - 1846 - 402 pages
...second term, and the other for the first. III. Finally, multiplying the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer... | |
 | James Bates Thomson - Arithmetic - 1846 - 362 pages
...second term, and the other for the first. IIL Finally, multiplying the second and third terms togethf-r, divide the product by the first, and the quotient will be the. answer in the same denomination as the third term. PROOF. — Multiply the first term ami the ansmr... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. Multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination as the third term. 3. If either... | |
 | Roswell Park - Best books - 1847 - 626 pages
...first. The question being thus stated, multiply the second and third terms together, and divide their product by the first; and the quotient will be the fourth term, or answer sought. A Compound Proportion, including the solution of problems by what is called the Double... | |
 | James Bates Thomson - Arithmetic - 1847 - 426 pages
...second term, and the other for the first. III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer... | |
 | Isaiah Steen - 1848 - 316 pages
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, multiply the second and third terms together, and divide the product by the first term; the quotient is the answer, or fourth proportional required; and it is always of the same denomination... | |
 | William B. Young - Ready-reckoners - 1848 - 320 pages
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen multiply the second and third Terms together, and divide the product by the first Term, the result will be the fourth Term or answer, in the same de nomination to which the third Term... | |
 | rev. Frederick Calder - 1848 - 190 pages
...and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then multiply the second and third terms together, and divide the product by the first: the quotient will be the answer or fourth term, expressed in the same denomination as that in which... | |
 | James Bates Thomson - Arithmetic - 1848 - 434 pages
...second term, and the other for the first. III. Finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the tame denomination as the third term. PROOF. — Multiply the first term and the answer... | |
 | Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...the least of the two remaining numbers fqr the second term, and the greater for the first term ; then multiply' the second and third terms together, and divide the -product by the first term, and the quotient will be the answer in the same name "of the third term EXAMPLES. 1. If 6 yards... | |
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... for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. 
