 | Elias Loomis - Algebra - 1858 - 394 pages
...quotient. 3. Multiply the divisor by this term, and subtract the product from the divide?id. 4. Divide ths first term of the remainder by the first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract... | |
 | Charles Davies - Algebra - 1859 - 324 pages
...Multiply t/ie divisor by this term of the quotient, and subtract the product from the dividend: Ш. Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product from... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...the quotient ; multiply the divisor by this term and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, for the second term of the quotient ; multiply the divisor by this second term, and subtract the product... | |
 | John Robertson (LL.D., of Upton Park sch.) - 1861 - 140 pages
...the dividend by that of the divisor, and set the result in the quotient ; (iii.) Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend ; (iv.) Bring down fresh terms (as may be required) from the dividend, and repeat the whole operation.... | |
 | Charles Davies - Algebra - 1861 - 322 pages
...quotient ; multiply the divisor by thi2 tern, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient; multiply the divisor by the second term, and subtract... | |
 | William Smyth - Algebra - 1861 - 496 pages
...whole divisor by the term of the quotient just found, and subtract the result from the dividend ; 3°. divide the first term of the remainder by the first term of ike divisor, the result will be the second term of the quotient , 4°. multiply the whole divisor by... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...the divisor, the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide...of the remainder by the first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract... | |
 | Paul Allen Towne - Algebra - 1865 - 314 pages
...the whole of the root, and write the result to the left of the remainder, as a part of the divisor; divide the first term of the remainder by the first term of the partial divisor, and place the result as the third term of the root, and also at the right of the partial... | |
 | Joseph Ray - Algebra - 1866 - 252 pages
...product from the remainder. 4. Double the terms of the root already found, for a partial divisor, and divide the first term of the remainder by the first term of the divisor, and annex the result both to the root and the partial divisor. Multiply the divisor thus increased, by... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...product from the remainder. 4th. Double the terms of the foot already found for a partial divisor, divide the first term of the remainder by the first term of the divisor, and proceed in a similar manner to find the other terms. 1. Find the square root of 4ajy+12aty-f 9x'—... | |
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Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. 
