 | Charles Davies - Algebra - 1842 - 284 pages
...quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by the second term, and subtract... | |
 | Charles Davies - Algebra - 1842 - 368 pages
...the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by this second term, and subtract... | |
 | George Roberts Perkins - Algebra - 1842 - 370 pages
...the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by this second term, and subtract... | |
 | Encyclopedias and dictionaries - 1842 - 538 pages
...for the square root of numbers in every point but this, that the new term is always found by dividing the first term of the remainder by the first term of the divisor. A couple of examples will suffice. Let it ba required to find the square root of 1 +2x+3x!+<lx*+ Гх*... | |
 | William Scott - Algebra - 1844 - 568 pages
...term of the quotient. Multiply the divisor by this term, and subtract the product from the quotient. . Divide the first term of the remainder by the first term of the divisor; the result is the second term of the quotient. Multiply the divisor by the second term of the quotient,... | |
 | James Bates Thomson - Algebra - 1844 - 272 pages
...term, for the first term of the required root : III. Subtract the power from the given quantity, and divide the first term of the remainder by the first term of the root in volved to the next inferior power and multiplied by the index of the given power ;* the quotient... | |
 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...term of the divisor, and place the quotient in the quotient, as its first term. Multiply every term of the divisor by the first term of the quotient, and subtract the product from the dividend, and oring down the remainder. Divide the first term of the remainder by the first term of the divisor,... | |
 | Elias Loomis - Algebra - 1846 - 380 pages
...the divisor, the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide...of the remainder by the first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract... | |
 | Elias Loomis - Algebra - 1846 - 376 pages
...the divisor, the result will be thefirst term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by t he first term of the divisor, the result will be the second term of the quotient. 5. Multiply the... | |
 | Samuel Alsop - Algebra - 1846 - 300 pages
...thus determined, and subtract the product from the dividend, arranging the terms as above directed. Divide the first term of the remainder by the first term of the divisor, and so proceed until the operation is accomplished. EXAMPLES. Ex. 1. a — x) a3 — 2 ax + x3 (a — x... | |
| |
Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. 
