 | Jeremiah Day - Measurement - 1831 - 520 pages
...what is the solidity ? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY £ OF THE HEIGHT. Let L and... | |
 | Tobias Ostrander - Measurement - 1833 - 172 pages
...when its ends are right parallelograms. " PROBLEM XVIII, To find the solidity of a prismoid. Rule—To the sum of the areas of the two ends, add four times the area of a section parallel to, and equally distant from, both ends, arid this last sum multiplied by •£... | |
 | William Templeton (engineer.) - 1833 - 224 pages
...gallons nearly as before. •» «bi2&' PROBLEM V. To find the Solid Content of the Frustum of a Pyramid. RULE. — To the sum of the areas of the two ends, add the square root of. their product, multiply this sum by the perpendicular height ; and i of the product... | |
 | Tobias Ostrander - Measurement - 1834 - 182 pages
...prismoid when its ends are right parallelograms. ~ ~ " PROBLEM XVIII. To find the solidity of a prismoid. Rule — To the sum of the areas of the two ends, add four times the area of a section parallel to, and equally distant from, both ends, arid this last sum multiplied by | of the... | |
 | 1834 - 882 pages
...at h.) Put the area ABCD=E. abcd=F. length = L. solidity = S. ThenS=jL.(Er-F+4G.)* Or, To the area of the two ends, add four times the area of the middle cross section : multiply by one sixth of ihe length. It is evident that the above solution holds true,... | |
 | Mathematics - 1836 - 488 pages
...hight of the wedge and the breadth of the base. To ßnd the solidity of a rectangular prismoid. To the areas of the two ends, add four times the area of a parallel section equally distant from the ends, and multiply the sum by ^ of the hight. A solid is... | |
 | Thomas Holliday - Surveying - 1838 - 404 pages
...and breadth of each end, and the perpendicular distance between them, for the solidity. Rule.—To the sum of the areas of the two ends, add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by one-sixth... | |
 | Jeremiah Day - Geometry - 1838 - 416 pages
...what is the solidity ? Ans. 5040, PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY £ OF THE HEIGHT, Let L and... | |
 | Jeremiah Day - Geometry - 1839 - 434 pages
...what is the solidity ? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY | OF THE HEIGHT. Let L and... | |
 | J. M. Scribner - Measurement - 1844 - 130 pages
...inches 1 Jlns. 32552 cubic ft. PROBLEM VIII. To find the Solidity of a Rectangular Prismoid. AKT. 45. Rule. — To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from the parallel ends, and this sum, multiplied by i of... | |
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RULE. To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends ; multiply this sum by the perpendicular height, and J of the product will be the solidity. 
