 | Scottish school-book assoc - 1845 - 444 pages
...perpendicular height 28 inches? Ans. 3 feet 444 inches. PROBLEM VII. To find the solidity of a prismoid. RULE. To the sum of the areas of the two ends add four times the area of a section, parallel to and equally distant from both ends ; multiply this sum by the perpendicular... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...height 25. Ans. surf. 1363.4544, sol. 3493.4592. PROBLEM 6. — To find the solidity of a prismoid. RULE. — To the sum of the areas of the two ends, add four times the area of a section parallel to, and equally distant from both ; this sum multiplied by one-sixth of the height,... | |
 | William Kelly (engineer.) - 1847 - 88 pages
...Interval. The usual rule for obtaining the content of a Prismoid as stated by Bonnycastle, is — " To the sum of the areas of the two ends, add four times the area of a section parallel to the two ends and equally distant from them, and this sum being multiplied by... | |
 | 458 pages
...with the result of their project in his behalf." rRODLEM X. To find the solidity of a prismoid. To the sum of the areas of the two ends add four times the area of a section parallel to the two ends and equally distant from them ; and this sum being multiplied by... | |
 | P. O'Shaughnessy (Civil engineer) - Civil engineering - 1848 - 110 pages
...or ca;nal are resolvable into prismoids, pyramids, and wedges. To find the solidity of a prismoid. Rule.— To the sum of the areas of the two ends add four times the area of a section parallel to, equally distant from' both ends; the last sum, multiplied into one-sixth the... | |
 | John Bonnycastle - Geometry - 1848 - 320 pages
...inches? Ans. 3.1006 feet. PROBLEM XL * t To find the solidity of a prismoid. • - . * . • iRULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by | of the... | |
 | Jeremiah Day - Logarithms - 1848 - 354 pages
...what is the solidity? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY -J- OF THE HEIGHT. Let L... | |
 | Almon Ticknor - Measurement - 1849 - 156 pages
...the solidity ? Ans. 2-9166 cubic feet. \ PROBLEM 20. To find the solidity of a prismoid. EULE. — To the sum of the areas of the two ends add four times the area of the section parallel to, and equally distant from both ends, and this last sum multiplied by J of the height... | |
 | Oliver Byrne - Engineering - 1851 - 310 pages
...inches. And 7140 -r- 1728 = 4-1319 solid feet, the content. To find the solidity of a prismoid. — To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by ^ of the... | |
 | Charles W. Hackley - Engineering - 1856 - 530 pages
...47 '75 gallons nearly, as before. PROBLEM VI. To find the solid content of the frustum of a pyramid. RULE. To the sum of the areas of the two ends add the square root of their product ; multiply this sum by the perpendicular height, and \ of the product... | |
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RULE. To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends ; multiply this sum by the perpendicular height, and J of the product will be the solidity. 
