 I label the two new points e and/.' With the help of this figure he then proceeds to the usual proof of the theorem that the area of a parallelogram is equal to the product of the base by the altitude, establishing the equality of certain lines and angles...  Second-year Mathematics for Secondary Schools - Page 341by Ernst Rudolph Breslich - 1916 - 348 pagesFull view - About this book
 | 1903 - 886 pages
...ft. X or 12 ft. X 514 ft. = 63 sq. ft.) j ft., 5 A 9 / k J FIG. 20.-AREAS OF TRIANGLES. Prop. XX. — The area of a parallelogram is equal to the product of the altitude multiplied by the base. (In Fig. 21 suppose the altitude k J of the rhomboid ghij to be 10... | |
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