 I label the two new points e and/.' With the help of this figure he then proceeds to the usual proof of the theorem that the area of a parallelogram is equal to the product of the base by the altitude, establishing the equality of certain lines and angles...  Second-year Mathematics for Secondary Schools - Page 341by Ernst Rudolph Breslich - 1916 - 348 pagesFull view - About this book
 | Charles H. Gleason - Arithmetic - 1910 - 536 pages
...by the altitude. 2. The area of a rectangle is equal to the product of the length by the breadth. 3. The area of a parallelogram is equal to the product of the base by the altitude. MENSURATION 4. The area of a trapezoid is equal to £ the sum of the two parallel... | |
 | Wilbur Fisk Nichols - 1910 - 236 pages
...brevity we usually say, to find the area of a parallelogram multiply the length by the width. 3. Since the area of a parallelogram is equal to the product of the two dimensions, it follows that if the area and one dimension are given the other may be found. 4.... | |
 | James Charles Byrnes, Julia Richman, John Storm Roberts - Arithmetic - 1911 - 328 pages
...with the old figure in area ? Therefore, how may you find the area of a parallelogram ? 222. RULE. The area of a parallelogram is equal to the product of the base by the altitude expressed in like units : DENOMINATE NUMBERS altitude is 3 ft., the area of the parallelogram... | |
 | George Wentworth, David Eugene Smith - Arithmetic - 1911 - 396 pages
...the parallelogram will be changed to a rectangle of the same base and the same altitude. Therefore, the area of a parallelogram is equal to the product of the numbers expressing the base and altitude. The base and the altitude must be expressed in the same units.... | |
 | Glenn Moody Hobbs - 1912 - 100 pages
...consequently, 2 , . , 2(A DXaltitude) . _ , . , the sum 01 these areas =— = A UXaltitude. 2, Rule: (b) The area of a parallelogram is equal to the product of the base and altitude. This will be true of any parallelogram and hence true of the rectangle, Fig. 34, the square,... | |
 | George Albert Wentworth, David Eugene Smith - Arithmetic - 1912 - 374 pages
...the parallelogram will be changed to a rectangle of the same base and the same altitude. Therefore, the area of a parallelogram is equal to the product of the base and altitude. Tor example, if the base of a parallelogram is 3 ft. 8 in. and the altitude is 3 ft., what... | |
 | George Morris Philips, Robert Franklin Anderson - Arithmetic - 1913 - 520 pages
...product of the number of units in the base and the number of units in the altitude; therefore: 448. The area of a parallelogram is equal to the product of the number of units in the base and the number of units in the altitude. NOTE. The base and altitude must... | |
 | George Wentworth - Plane trigonometry - 1914 - 348 pages
...¿ = 32.78, с = 29.62, A = 57° 32' 20". 10. b = 1487, с = 1634, A = 61° 30' 30". 11. Prove that the area of a parallelogram is equal to the product of the base, the diagonal, and the sine of the angle included by them. 12. Find the area of the quadrilateral ABCD,... | |
 | Education - 1915 - 396 pages
...it at X, the parallelogram will be changed to a rectangle of the same base and altitude. Therefore, the area of a parallelogram is equal to the product of the numbers expressing the base and altitude. Written. — Find the areas of parallelograms with the following... | |
 | William Timothy Stratton, Benjamin Luce Remick - Arithmetic - 1916 - 264 pages
...seen that any parallelogram may be made into a rectangle having the same base and altitude. Therefore, the area of a parallelogram is equal to the product of the base by the altitude. Formula : Area = base x altitude. The figure above shows that the diagonal divides... | |
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