 | Roswell Chamberlain Smith - Arithmetic - 1838 - 304 pages
...12. ч Hence, When the Extremes and Common Difference are given, to find the JVwmber of Terms ; — Divide the difference of the extremes by the common...difference, and the quotient, increased by 1, will be th« answer. 17. If the extremes be 3 and 45, and the common difference 6, what is the Dumber of terms... | |
 | Nathan Daboll - 1839 - 220 pages
...miles 3 furlongs 100 yards. CASE IV. TAe first term, last term and common difference given, to find the number of terms. RULE. Divide the difference of...by. 3 cents to the last, which was 53 cents ; how manv yards did he buy ? Extremes*53 We found (Case 2, Ex. 1, fcxtremesj^ (hat thg difference of the... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...basket ? Ans. 288090 miles, 2 rods. PROBLEM HI. Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of...the common difference, and the quotient increased by one, will be the number of terms required. 9. If the extremes are 3 and 45, and the common difference... | |
 | Roswell Chamberlain Smith - 1839 - 308 pages
...Л. 12. Hence, When the Extremes and Common Difference are given, In Jim L the Number of Terms ; — Divide the difference of the extremes by the common...difference, and the quotient, increased by 1, will be the answer. 17. If the extremes he 3 and 45, and the common difference 6, what is the number of terms ?... | |
 | Frederick Emerson - Arithmetic - 1839 - 300 pages
...and also the number of miles travelled. PROBLEM in. The extremes and common difference given, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient; the sum will be the number of terms. The difference of the extremes divided... | |
 | Frederick Emerson - Arithmetic - 1839 - 300 pages
...miles travelled. PROBLEM in. The extremes and common difference given, to find the number of term?. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient; the sum •will be the number of terms. The difference of the extremes divided... | |
 | Calvin Tracy - Arithmetic - 1840 - 316 pages
...8+1=9, the whole number of terms, or answer required. From the above we derive the following rule : RULE. — Divide the difference of the extremes by the common difference, and add one to the quotient. 2. A man commenced a journey, and traveled the first day only 4 miles ; after... | |
 | Arithmetic - 1841 - 200 pages
...distance 366m. •«* CASE IV. Given the first term, the last term, and the common difference, to find the number of terms. RULE. — (') Divide the difference...the common difference, and the quotient increased by one is the number of terms required. Question. — 1. The first and last terras, and common difference... | |
 | Benjamin Greenleaf - Arithmetic - 1841 - 334 pages
...basket ? Ans. 288090 miles, 2 rods. PROBLEM IIL Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of...the common difference, and the quotient increased by one, will be the number of terms required. 9. If the eXtremes are 3 and 45, and the common difference... | |
 | Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...18. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common...difference, and the quotient, increased by 1, will be the ainicer. 3-2. If the extremes be 3 and 45, and the common difference 6. what is the number of terms*... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
