 | Nicolas Pike - Arithmetic - 1832 - 538 pages
...9+fl+9+9+9+9+9+9=9x8="2, an'i 42 ¡-8=— =3f. PROBLEM III, tiivtn the extremes and the common difference, to find the number of \ terms. RULE.* Divide the difference...difference, and the quotient increased by 1 will be the mira- , her of terms required. EXAMPLES. fst. The extremes are 3 and 39, and the common difference... | |
 | Nathan Daboll - Arithmetic - 1823 - 262 pages
...the U'hok debt. • .. PJRbBLEM III. Given the first term, last ternl, and common difference, to fmd the number of terms. RULE. «* " Divide the difference of the extremes by (he common difi'eixMiee, and the quotient increased by 1 is the number of terms. • " EXAMri.rs 1.... | |
 | Nathan Daboll - Arithmetic - 1824 - 264 pages
...9 ! 2i. the u'holt PROBLEM III. UiveB the first term, last term, and common dSftcren«v. ti• find the number of terms. RULE. Divide the difference of the extremes by the common diffbrence, and the quotient increased by 1 is t!ic nunibei of terms. F.XAMT-l.KS. 1. If the extremes... | |
 | Nathan Daboll - Arithmetic - 1825 - 256 pages
...ichott PROBLEM III. triv*a tha first term, last term, and common different* to find the number of term*. RULE. Divide the difference of the extremes by the...common difference, and the quotient increased by 1 is the nnmbei •f terms. EXAMPLES. 1. If the extremes be 3 and 45, an'1 the common dif Jbrence 2 ;... | |
 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...ages ? Ans. 3 years. Problem III. The first term, the last term, and common difference given, to find the number of terms. RULE.! — Divide the difference...common difference, and the quotient, increased by 1, is the number of terms required. Examples. 1. The extremes are 2 and 53, and the common difference... | |
 | Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
...one to the basket ? A. 7042 miles. PROBLEM II. — Given the extremes and common difference to find the number of terms. RULE. — Divide the difference...common difference, and the quotient increased by 1, is the answer. EXAMPLES. — If the extremes be 3 and 45, and the common difference 6 ; what is the... | |
 | B. M. Tyler - Arithmetic - 1827 - 308 pages
...21 miles, and the last 70; — how many miles does he increase daily ? Ans. 7. PROBLEM IV. To find the number of terms. • RULE. Divide the difference of the extremes by the common difference, and add one to the quotient. Illustration. — The greatest term is made up of the common difference added... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...distance 455 miles. PROB. III. — Given the first term, last term, and common difference, to find the number of terms. RULE. Divide the difference of...the common difference, and the quotient increased by one, is the number of terms. Examples. 1. Let the extremes be 5 and 53, and the common difference 6... | |
 | Nathan Daboll - Arithmetic - 1828 - 268 pages
...and9lZl. the whole debt. PROBLEM III. Given the first term, last term, and common difference, to find the number of terms. RULE.' * Divide the difference of the extremes by the common difference, aml the quotient increased by 1 is the number of tanns. EXAMPLE8. 1. If the extremes be 3 and 45, and... | |
 | William Kinne - 1829 - 246 pages
...Ans. 4 years. PROBLEM 111. Given the first term, the last term, and the common difference, to find the number of terms. RULE. — Divide the difference...common difference, and the quotient increased by 1, is the number of terms required. EXAMPLES. 1. The extremes are 3 and 19, and the common difference... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
