In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which... Elements of Algebra - Page 31by William Smyth - 1847Full view - About this book
| Edward Albert Bowser - Algebra - 1888 - 868 pages
...bc+bd (Art. 33). . . (4) Hence, to multiply one polynomial by another, we have the following RULE. Multiply each term of the multiplicand by each term of the multiplier; if the terms multiplied together have the same sign, prefix the sign + to the product, if unlike, prefix... | |
| William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 428 pages
...by-\-bz. Hence, for the multiplication of a polynomial by a polynomial, we have the following Ru1e. • Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply 2 x2 + 3 xy — if by 3 x — 2 y. 2x* + 3xy... | |
| Webster Wells - Algebra - 1890 - 560 pages
...Polynomials. By Art. 60, (1), = ac + be + ad + bd, by Art. 60, (5). "We then have the following rule : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 1. Multiply 3a - 2 b by 2a - 56. In accordance with the rule, we multiply... | |
| William James Milne - Algebra - 1894 - 216 pages
...a + 6 a times a + 6 = a2 + a6 6 times a + b = a6 + 62 (a + 6) times (a + 6) = a2 + 2 a6 + 62 RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 2 а6 - 3 с 4а6 + c 8a2f>2-12a6c 2 aЬc - 3 с2 8a262- 10 a6c -3с2... | |
| William Frothingham Bradbury, Grenville C. Emery - Algebra - 1894 - 144 pages
...this equals Hence, for the multiplication of a polynomial by a polynomial, we have the following Bule. Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply За2 — 2а6 + 462 by 2a — 3b. 3 a* — 2... | |
| William James Milne - Algebra - 1894 - 214 pages
...a + 6 а times a + b = a2 + ab b times a + b = ab + b1 (a + 6) times (a + 6) = a2 + 2 ab + 62 BULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 2a6-3c 4 ab + с 8 a262- 12aftc 2 a6c - Я с2 8cW- 10 a6c -3с3 Multiply... | |
| Edward Brooks - Arithmetic - 1895 - 424 pages
...placing terms of the same order in the same column, and draw a line beneath. II. Begin at the right, and multiply each term of the multiplicand by each term of the multiplier, writing the first term of each product under the term of the multiplier used to obtain it. III. Add... | |
| George Washington Hull - Algebra - 1895 - 358 pages
...products, we 2a2 + ab - 662, Ans. have 2aJ + 06 - 66Z. From this example we derive the following RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. m2 + 2mn + w2, ^4ns. m2 — 2mn + n2 m'1 5. 6. a4 + rt'6 + a262 x*-x«... | |
| Fletcher Durell, Edward Rutledge Robbins - Algebra - 1897 - 482 pages
...Polynomials. The Distributive Law applies here as in ordinary algebraic multiplication of polynomials; hence, Multiply each term of the multiplicand by each term of the multiplier ; Simplify each term of the result, and collect. Ex.1. Multiply 31/2 + 5 1/3 by 31/2-1/3: 31/2" + 51/3... | |
| 1897 - 358 pages
...Ans. (14) In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces... | |
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