In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which... Elements of Algebra - Page 31by William Smyth - 1847Full view - About this book
| Edward Olney - Algebra - 1880 - 354 pages
...completed. 84. Prob. — To multiply two factors together when one or both are polynomials. R ULE. — MULTIPLY EACH TERM OF THE MULTIPLICAND BY EACH TERM OF THE MULTIPLIER, AND ADD THE PRODUCTS. DEM. — Thus, if any quantity is to be multiplied by a + Ъ — e, if wo take... | |
| James Bates Thomson, Elihu Thayer Quimby - Algebra - 1880 - 360 pages
...Multiplication of Polynomials. The Multiplication of Polynomials is performed by the following RULE. — Multiply each term of the multiplicand by each term of the multiplier, and add the products. NOTES. — i. This does not differ in principle from the method of multiplying... | |
| Edward Olney - Algebra - 1881 - 254 pages
...partial products I have 15z 2 — z—8z 2 , which is 5x + 3y-2z times 3z— 2y+4z. . 28. RULE. — Multiply each term of the multiplicand by each term of the multiplier, and add the products. 2. Multiply 3a 3 5-2«5 3 +53 by2a5+52. OPERATION. + 3a 3 b 3 — Prod., 6a35... | |
| William James Milne - Algebra - 1881 - 360 pages
...these two partial products is the entire product. Hence, the product is 2z2 — 3xy — 2y2. RULE. — Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. (2.) (3.) Multiply ab + 2c 3.T2 — any By 2ab — 3c 2z2 + Saxy 2a262... | |
| Edwin Pliny Seaver, George Augustus Walton - Algebra - 1881 - 304 pages
...arrangement. 107. From these examples may be derived a Rule for the Multiplication of Polynomials. Multiply each term of the multiplicand by each term of the multiplier, and add the results. 108. Exercises. 267. Multiply 1 — 2a* + 36ar ! by3n. 268. Multiply 2 ax + by... | |
| Simon Newcomb - Algebra - 1882 - 302 pages
...before. We have therefore the following rule for multiplying one polynomial by another. 119. RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the products with their proper algebraic signs. EXERCISES. 1. (m - n) (p - q). Solution, (m... | |
| Webster Wells - 1885 - 368 pages
...d was ac — be — aci + 6d. We have then the following rule for the product of two polynomials : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. EXAMPLES. 1. Multiply Зa — 26 by 2a — 56. In accordance with the... | |
| Webster Wells - Algebra - 1885 - 324 pages
...d was аc — be — ad + &d. We have then the following rule for the product of two polynomials : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. EXAMPLES. 1. Multiply За — 2& by 2 а — 5&. In accordance with... | |
| Horatio Nelson Robinson - 1888 - 372 pages
...I. Write the several terms of the multiplier under the corresponding terms of the multiplicand. II. Multiply each term of the multiplicand by each term of the multiplier, beginning with the lowest term in each, an I call the product of any two denominations the denomination... | |
| Edward Brooks - Algebra - 1888 - 190 pages
...partial 2a2 — ab products, we have 2a2+3a6- 262. Therefore, etc. +4a6-26' 2a2 + 3a6-26« Rule. — Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. a — 6 a +6 a2-a6 +a6-62 a3 -62 (6.) an-6" a2-6' a8 -62 an+Ja"68-a26"+6"+3... | |
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