 | Elias Loomis - Algebra - 1855 - 356 pages
...remainder by the first term oj the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation till all the terms of the dividend are exhausted. If the... | |
 | Elias Loomis - Algebra - 1856 - 280 pages
...remainder by the first term of the divisor ; the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation till all the terms of the dividend are exhausted. If the... | |
 | Joseph Ray - Algebra - 1857 - 408 pages
...dividend. Divide the first term of the dividend by the first term of the divisor ; the result will be the first term of the quotient. Multiply the divisor by...term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor; the result will be the second... | |
 | Charles Davies - Algebra - 1857 - 408 pages
...divide the first term on the left of the dividend by the first term on the left of the divisor, for the first term of the quotient; multiply the divisor by this term and subtract the product from ike dividend. II. Then divide the fast term of the remainder f>y the first term of the divisor, for... | |
 | Samuel Alsop - 1857 - 150 pages
...thus determined, and subtract the product from the dividend, arranging the terms as above directed. Divide the first term of the remainder by the first term of the divisor, and so proceed until the operation is accomplished. EXAMPLES. Ex. 1. Divide cf — 2 oc + a? by o —... | |
 | William Smyth - Algebra - 1858 - 344 pages
...whole divisor by the term of the quotient just found, and subtract the result from the dividend ; 3°. divide the first term of the remainder by the first term of the divisor, the result will be the second term of the quotient, 4°. multiply the whole divisor by the second term... | |
 | Elias Loomis - Algebra - 1858 - 394 pages
...quotient. 3. Multiply the divisor by this term, and subtract the product from the divide?id. 4. Divide ths first term of the remainder by the first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract... | |
 | Charles Davies - Algebra - 1859 - 324 pages
...dividend: Ш. Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product from the first remainder, and so on : IV. Continue the operation, until a remainder is found equal to 0, or... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...divide the first term on the left of the dividend by the first term on the left of the divisor, for the first term of the quotient ; multiply the divisor...of the remainder by the first term of the divisor, for the second term of the quotient ; multiply the divisor by this second term, and subtract the product... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...on the lefi of the dividend by the first term on the left of the divisor, for the first term of th« quotient ; multiply the divisor by this term and subtract...dividend. II. Then divide the first term of the remainder 1'y the first term of the divisor, for the second term of the quotient ; multiply the divisor by this... | |
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Then divide the first term of the remainder by the first term of the divisor... 
