 | Harvey Goodwin - Mathematics - 1846 - 500 pages
...the two; the division of the first term of the dividend by the first term of the divisor gives the first term of the quotient ; multiply the divisor...this term, and subtract the product from the dividend ; bring down as many more of the terms of the dividend as may be required, and repeat the process until... | |
 | Samuel Alsop - Algebra - 1846 - 300 pages
...thus determined, and subtract the product from the dividend, arranging the terms as above directed. Divide the first term of the remainder by the first term of the divisor, and so proceed until the operation is accomplished. EXAMPLES. Ex. 1. a — x) a3 — 2 ax + x3 (a —... | |
 | Elias Loomis - Algebra - 1846 - 380 pages
...remainder by the first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation, and if you obtain 0 for a remainder, the division is said... | |
 | Elias Loomis - Algebra - 1846 - 376 pages
...remainder by t he first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation, and if you obtain 0 for a remainder, the division is said... | |
 | Davis Wasgatt Clark - Algebra - 1846 - 374 pages
...Divide the first term of this new dividend by the first term of the divisor ; the result is the second term of the quotient. Multiply the divisor by this term, and subtract as before. 5. Proceed in this manner till the dividend has been exhausted, or till no term of the remainder... | |
 | Algebra - 1847 - 408 pages
...dividend by the first term on the left of the divisor, for the first term of the quotient; muliply the divisor by this term and subtract the product...of the remainder by the first term of the divisor, for the second term of the quotient; multiply the divisor by this second term, and subtract the product... | |
 | George Roberts Perkins - Algebra - 1847 - 432 pages
...first term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the divisor...term, and subtract the product from the dividend. II. Tfien divide the first term of the remainder by thefirst term of the divisor, which gives the second... | |
 | Algebra - 1847 - 386 pages
...dividend by the first term on the left of the divisor, for the ßrst term of the quotient; muliply the divisor by this term and subtract the product from the dividend. II. Then divide the ßrst term of the remainder by the ßrst term of the divisor, for the second term of the quotient ;... | |
 | Jeremiah Day - Algebra - 1847 - 358 pages
...term, for the first term of the required root : • Subtract the power from the given quantity, and divide the first term of the remainder, by the first term of the root involved to the next inferior power, and multiplied by the index of the given power ;f the quotient... | |
 | George Roberts Perkins - Algebra - 1848 - 234 pages
...term on the left of the dividend by the first term, on the left of the divisor, the result is the fast term of the quotient; multiply the divisor by this...the product from the dividend. \ II. Then divide the fast term of the remainder by the fast term of the divisor, which gives the second term of the quotient;... | |
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Then divide the first term of the remainder by the first term of the divisor... 
