 | William James Milne - Geometry - 1899 - 404 pages
...parallelogram is equal to the product of its base by its altitude. 333. Cor. II. Parallelograms are to each other as the products of their bases by their altitudes; consequently, parallelograms which have equal altitudes are to each other as their bases, parallelograms... | |
 | Harvard University - Geometry - 1899 - 39 pages
...of two rectangles having equal altitudes are to each other as their bases. THEOREM III. The areas of two rectangles are to each other as the products of their bases and their altitudes. Corollary. The area of a rectangle is equal to the product of its base and its... | |
 | Webster Wells - Geometry - 1899 - 196 pages
...2. Two prisms having equivalent bases are to each other as their altitudes. 3. -Any two prisms are to each other as the products of their bases by their altitudes. 289 PYRAMIDS. DEFINITIONS. 502. A pyramid is a polyedron bounded by a polygon, called the base, and... | |
 | George Albert Wentworth - Geometry - 1899 - 500 pages
...its altitude. To prove that the area of H = a X b. Proof. Let U be the unit of surface. R a X b U 1X1 (two rectangles are to each other as the products of their bases and altitudes). • = a X b, § 397 But jj = the number of units of surface in R. § 393 .'. the area... | |
 | Education - 1900 - 612 pages
...third line making the alternate angles equal the two lines are parallel. 5 Prove that the areas of any two rectangles are to each other as the products of their bases and altitudes. Second 6 The sides of a triangle are 3 feet, 5 feet and 7 feet division respectively;... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...altitudes. For their altitudes may be regarded as bases, and their bases as altitudes. PROPOSITION III. — THEOREM. Any two rectangles are to each other as the products of their bases by their altitudes. Given. — Let R and R' represent two rectangles whose bases are respectively 6 and b', and altitudes... | |
 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...of the former rectangle is 96 sq. ft. What is the area of the other ? PROPOSITION IV. THEOREM 584. Any two rectangles are to each other as the products of their bases and altitudes. Let ABCD and EFGH be any two rectangles. AB CD AD X AB To Prove EFGH EH X EF Proof.... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...given one as m : n, when m and n are two given lines. PROPOSITION II. THEOREM • 338. The areas of two rectangles are to each other as the products of their bases and altitudes. Hyp. Rectangles R and R' have the bases b and b' and the altitudes a and a' respectively.... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...rectangle whose area is f of the given one. PLANE GEOMETRY PROPOSITION II. THEOREM 338. The areas of two rectangles are to each other as the products of their bases and altitudes. Hyp. Rectangles R and R' have the bases b and b' and the altitudes a and a' respectively.... | |
 | Arthur Schultze - 1901 - 260 pages
...cut off another rectangle whose area is f of the given one. PROPOSITION II. THEOREM 338. The areas of two rectangles are to each other as the products of their bases and altitudes. Hyp. Rectangles R and R' have the bases b and b' and the altitudes a and a' respectively.... | |
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Any two rectangles are to each other as the products of their bases by their altitudes. 
