 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 276 pages
...Two rectangles having equal altitudes are to each other as their bases. PROPOSITION III. THEOREM 380. Any two rectangles are to each other as the products of their bases and altitudes. GIVEN—any two rectangles, R and R', their bases being b and b', and altitudes a and... | |
 | New York (State). Legislature. Senate - Government publications - 1897 - 1306 pages
...4-5 State and prove a theorem, the conclusion of which is, the triangles are similar. 6-7 Prove that any two rectangles are to each other as the products of their bases and altitudes. 8 Derive an expression for the area of a regular triangle whose side is s. 9 State in... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 374 pages
...a linear unit. To PROVE—area of R = a X b, provided U is the unit of area. R_aX b_ [The areas of two rectangles are to each other as the products of their bases and altitudes.] But - = area of R. § 355 [The area of a surface is the ratio of that surface to the... | |
 | George Washington Hull - Geometry - 1897 - 408 pages
...second parallelogram, with a and b its altitude and base respectively. COR. 1.—Two parallelograms are to each other as the products of their bases by their altitudes. For P= A X B, and p — a X b (§ 229). COR. 2.— Two parallelograms having equal bases are to each... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 376 pages
...unit. To PROVE — area of R = a X b, provided U is the unit of area. ^rlrr"**- §361 [The areas of two rectangles are to each other as the products of their bases and altitudes.] P But - = areaofAJ. §355 [The area of a surface is the ratio of that surface to the... | |
 | Arthur A. Dodd, B. Thomas Chace - Geometry - 1898 - 468 pages
...angle between a secant and a tangent is measured by one-half the difference of the intercepted arcs. 6. Any two rectangles are to each other as the products of their bases by their altitudes. 7. The area of a circle is equal to one-half the product of its circumference and radius. 8. A regular... | |
 | Webster Wells - Geometry - 1898 - 250 pages
...Since either side of a rectangle may be taken as the base, it follows that PROP. ii. THEOREM. 301. Any two rectangles are to each other as the products of their bases by their altitudes. V Given M and N rectangles, with altitudes a and a', and bases 6 and b ' , respectively. To Prove M... | |
 | James Howard Gore - Geometry - 1898 - 232 pages
...The area of a rectangle is equal to the product of its base and altitude. It is known (from 247) that two rectangles are to each other as the products of their bases by their altitudes ; therefore, but S is the unit of area ; hence R = h x b. 249. COB. If h = b, then R = bxb = b*. But... | |
 | Webster Wells - Geometry - 1898 - 264 pages
...2. Two triangles having equal bases are to each other as their altitudes. 3. Any two triangles are to each other as the products of their bases by their altitudes. PROP. VI. THEOREM. 316. The area of a trapezoid is equal to one-half the sum of its bases multiplied... | |
 | Arthur A. Dodd, B. Thomas Chace - Geometry - 1898 - 468 pages
...parallelograms having equal bases are to each other as their altitudes; and any two parallelograms are to each other as the products of their bases by their altitudes. 260. 261. Cor. V. Can you show how to find the area of any triangle ? 262. Cor. VI. Can you show that... | |
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Any two rectangles are to each other as the products of their bases by their altitudes. 
