 | Lucius D. Gould - Carpentry - 1853 - 234 pages
...the axis by -5236 ; the product will be the solidity. To find tlie Solidity of a Spherical Segment. Rule. — To three times the square of the radius...multiply the sum by the height, and the product by -5236. To find the Solidity of a Spherical Zone or Frustum. Rule. — To the sum of the squares of the radius... | |
 | Septimus Norris - Locomotives - 1854 - 334 pages
...by -5236 ; the product will be the solidity. To find the Solidity of a Spherical Segment, fig. 34. RULE. — To three times the square of the radius...multiply the sum by the height, and the product by -5236. To find the Solidity of a Spherical Zone or Frustum, fig. 35. RULE. — To the sum of the squares of... | |
 | Lucius D. Gould - 1857 - 464 pages
...by 5236 ; the product will be the solidity. To find the Solidity of a Spherical &gment. Rv2e.—To three times the square of the radius of its base,...multiply the sum by the height, and the product by 5236. - ¿.. To find the &lidity of a Spherical Zone or F¿t¿m. Rule.—To the sum of the squares of the... | |
 | Augustus Frederick Oakes - 1857 - 98 pages
...height, and this product by -5236. 2. Or, to three times the square of the radius of the segment's base add the square of its height ; then multiply the sum by the height, and the product by '5236. To find the quantity of powder to fill the cbamber of a Mortar or Howitzer. Multiply the content of... | |
 | Charles Haynes Haswell - Measurement - 1858 - 350 pages
...Definition. A section of a sphere. To ascertain the Contents of a Segment of a Sphere, Fig. 98. RULE 1. To three times the square of the radius of its base add the square of its height ; multiply this sum by the height, and the product, multiplied by .5236, will give the contents required.... | |
 | Frederick Augustus Griffiths - Artillery - 1859 - 426 pages
...height, and this product by • 5236. 2. Or, to three times the square of the radius of the segment's base add the square of its height ; then multiply the sum by the height, and the product by -5236. Example. — Required the content of a spherical segment 2 feet in height, cut from a sphere of 8 feet... | |
 | Joseph Roberts - Artillery - 1860 - 202 pages
...the height, and this product by .5236; or, to three times the square of the radius of the segment's base, add the square of its height, then multiply the sum by the height, and this product by .5236, for the content. 26. How is the capacity or content of a Gomer chamber computed... | |
 | Charles Hutton - Mathematics - 1860 - 1020 pages
...<x>ntent. Н'т.к u. — 'lo three times the square of the radius ol the segment's base, :•'•) the square of its height ; then multiply the sum by the height, and the тЛтЛ by -5236, for the content. ) x. I To find the content of a spherical segment, of 2 fe«t in... | |
 | S. M. Saxby - Marine engines - 1862 - 200 pages
...diameter and multiply by -5236 (= 3 ^16) ; the product will be the solidity. The segment of a sphere. — To three times the square of the radius of its base...the sum by the height, and the product by •5236. The cylindrical ring. — Add the inner diameter to the thickness of the ring, multiply the sum by... | |
 | Oliver Byrne - Engineering - 1863 - 600 pages
...inches. And 2572-4468 -^ 1728 = 1-48868 solid feet. To find the solidity of the segment of a sphere. — To three times the square of the radius of its base add the square of its height, and this sum multiplied by the height, and the product again by -5236, will give the solidity. Or,... | |
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... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents. 
