 | James Gallier - Building - 1836 - 228 pages
...the axis by .5236 ; the product will be the solidity. To find the Solidity of a Spherical Segment. RULE. — To three times the square of the radius...multiply the sum by the height, and the product by .5236. To find the Solidity of a Spherical Zone or Frustum. RULE. — To the sum of the squares of the radius... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 pages
...sphere ? To 3 times the square of the radius of the base of the segment, add the square of its height ; multiply the sum by the height, and the product by -5236 for the solidity. What is the solidity of a spherical segment of which the height is 2 feet, and the radius... | |
 | Frederick Augustus Griffiths - 1839 - 348 pages
...the height, and this product by -5236. Or, To three times the square of the radius of the segment's base add the square of its height; then multiply the sum by the height; and the product by 5236. To find the diameter of a sphere, its solidity being given. Divide the solidity by "5-236 and take... | |
 | Frederick Augustus Griffiths - 1840 - 436 pages
...2. Or, To three times the square of the radius of the segment's base add the square of its height j then multiply the sum by the height, and the product by -5236. Example.— Required the contentof a Spherical Segment, 2 feet in height, cut from a Sphere of 8 feet... | |
 | John Bonnycastle - Measurement - 1842 - 318 pages
...two-thirds of its circurascribing cylinder. PROBLEM XIV. To find the solidity of the segment of a sphere. RULE.* To three times the square of the radius of its base add he square of its height; and this sum multiplied by the height, and the product again by .5236, will... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 208 pages
...by the decimal .5236 for the contents ; or to three times the square of the radius of the segment's base, add the square of its height ; then multiply...height, and the product by .5236 for the contents. 2O. To find how large a cube may be cut from any given sphere, or be inscribed in it. RULE. Square... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 204 pages
...contents ; or to three times• the square of the radius of the segment's base, add the square of its N* height ; then multiply the sum by the height, and the product by .5236 for the contents. 50. To find how large a cube may be cut from any given sphere, or be inscribed in it. RULE. Square... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...by .5236, and the proclnct is the solidity. To find the Solidity of a Spherical Segment— fig. 38. RULE. — To three times the square of the radius of its base ab, add the square of its height cb ; then multiply this sum by the height, and the product by .5236.... | |
 | Benjamin Greenleaf - Arithmetic - 1845 - 222 pages
...contents ; or to three times the square of tlie radius of the segment's base, add the square of its N* height ; then multiply the sum by the height, and the product by .5236 for the contents. SO. To find how large a cube may be cut from any given sphere, or be inscribed in it. RULE. Square... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...to three times the square of the radius ot the base of the segment, add the square of the height ; multiply the .sum by the height, and the product by .5236 for the solidity. + The complement of 36° 52' is 53° 8', the natural sine of which is .800034 ; and 1 : 4000... | |
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... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents. 
