 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  A system of arithmetic - Page 70by John Husband (math. master, Berwick.) - 1841Full view - About this book
 | William Frothingham Bradbury - Arithmetic - 1879 - 392 pages
...divisor, and the sum will be the true divisor. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods... | |
 | C. Frusher Howard - Ready-reckoners - 1880 - 146 pages
...part; to the sum annex two ciphers, complete the divisor as before. 5. Multiply the complete divisor by the second figure in the root, subtract the product from the dividend and bring down the next period. 7. Repeat the foregoing process with each period until the exact root,... | |
 | Horatio Nelson Robinson - 1875 - 472 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure irt the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | A. Melrose - 1881 - 314 pages
...root and on the right of the divisor ; then multiply the divisor thus completed by this figure, and subtract the product from the dividend, and to the remainder annex the neit period for a new dividend. To the completed divisor add the figure last placed in the root, for... | |
 | William James Milne - Algebra - 1881 - 360 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus.... | |
 | H. Bryant - 1881 - 574 pages
...trial divisor; the sum mil be the true divisor. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 5. Add twice the root figure last found to the last term in column... | |
 | Alexander Ingram - 1881 - 192 pages
...divisor and to the last figure of the root ; then multiply the divisor thus completed by this figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 4. Add the last figure of the root to the last complete divisor for... | |
 | Arithmetic - 1882 - 526 pages
...divisor, thus forming the complete divisor. 2. Multiply the complete divisor by t/ie second figure of the root ; subtract the product from the dividend ; and to the remainder annex the next period for a dividend. IV. To find the succeeding figures of the root : — Proceed with t/ie... | |
 | James Bates Thomson - Arithmetic - 1882 - 416 pages
...the square of this second figure. . V. Multiply the divisor thus completed by the last figure placed in the root. Subtract the product from the dividend; and to the right of the remainder bring down the next period for a new dividend. Find a new trial divisor as before,... | |
 | James Gray - Arithmetic - 1883 - 154 pages
...and annex it also to the divisor. 4. Multiply the divisor thus completed by the last figure placed in the root : subtract the product from the dividend, and to the remainder bring down the third period for a new dividend ; proceed in the same manner till all the periods are... | |
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