Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... A system of arithmetic - Page 70by John Husband (math. master, Berwick.) - 1841Full view - About this book
| Dana Pond Colburn - Arithmetic - 1860 - 388 pages
...Multiply tlie true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true... | |
| James Stewart Eaton - 1862 - 320 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods... | |
| Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...the root to the trial divisor for a complete divisor ; multiply the complete divisor Ъу the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand... | |
| Charles Davies - Arithmetic - 1863 - 346 pages
...root, and also annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but... | |
| Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...(lie root to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period fur a new diuidend. V. Take the last complete divisor, doubling its right-hand... | |
| James Stewart Eaton - Arithmetic - 1864 - 322 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods... | |
| Elias Loomis - Algebra - 1864 - 386 pages
...root, and the square of the second figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole... | |
| John Purdue Bidlake - Arithmetic - 1866 - 232 pages
...root-figure. Cube the two figures of the root and subtract the result from the first two periods ; and to the remainder annex the third period for a new dividend. Divide this dividend by 300 times the square of the two root-figures already found, the quotient will... | |
| Joseph Ray - Algebra - 1866 - 250 pages
...and also on the right of the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor,... | |
| Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the... | |
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