 In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice the product of one of these sides and the projection of the other side upon it.  Schultze and Sevenoak's Plane and Solid Geometry - Page 193by Arthur Schultze, Frank Louis Sevenoak - 1913 - 457 pagesFull view - About this book
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...322. In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice...sides and the projection of the other side upon it. c .D Hyp. In Aa6c, p is the projection of b upon c, and the angle opposite a is obtuse. To prove a2... | |
 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...obtuse-angled triangle the square of the side opposite the obtuse angle is equivalent to the sum of the squares of the other two sides, increased by twice...sides and the projection of the other side upon it. B Let ABC be an obtuse-angled A, and CD be the projection of BC on AC (prolonged). To Prove AB2 = BC'2... | |
 | Arthur Schultze - 1901 - 260 pages
...322. In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice...sides and the projection of the other side upon it. JD Hyp. In Aabc, p is the projection of 6 upon c, and the angle opposite a is obtuse. To prove a 2... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...322. In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice...sides and the projection of the other side upon it. c Hyp. In Aabc, p is the projection of 6 upon c, and the angle opposite a is obtuse. To prove a2 —... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...triangle, the square on the side opposite the obtuse angle is equivalent to the sum of the squares on the other two sides increased by twice the product of one of those sides and the projection of the other upon that side. Given. — Let ABC be a triangle, of which... | |
 | Alan Sanders - Geometry - 1903 - 396 pages
...obtuse-angled triangle the square of the side opposite the obtuse angle is equivalent to the sum of the squares of the other two sides, increased by twice...sides and the projection of the other side upon it. B Let ABC be an obtuse-angled A, and Cn be the projection of BC on AC (prolonged). To Prove AJ? = «C'2... | |
 | Education - 1903 - 630 pages
...the side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of these sides and the projection of the other side upon it. 7. Prove : The area of a regular polygon is equal to one-half the product of its perimeter and apothem.... | |
 | Alan Sanders - Geometry - 1903 - 392 pages
...opposite an acute angle is equivalent to the sum of the squares of the other two sides, diminished by twice the product of one of these sides and the projection of the oiher side upon it. b B Let ABC be a A in which BC lies opposite an acute angle, and AD is the projection... | |
 | Fletcher Durell - Geometry - 1911 - 553 pages
...350. In any obtuse triangle, the square of the side opposite an obtuse angle is equal to the sum of the squares of the other two sides, increased by twice the product of one of the sides by the projection of the other side upon that side. A CD Given the obtuse /.ACE in the A... | |
 | George Albert Wentworth - Geometry - 1904 - 496 pages
...376. In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides increased by twice the product of one of those sides by the projection of the other upon that side. Let C be the obtuse angle of the triangle... | |
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