 In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice the product of one of these sides and the projection of the other side upon it.  Schultze and Sevenoak's Plane and Solid Geometry - Page 193by Arthur Schultze, Frank Louis Sevenoak - 1913 - 457 pagesFull view - About this book
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 276 pages
...of the side opposite an acute angle is equal to the sum of the squares of the other two sides, minus twice the product of one of these sides and the projection of the other side upon it. GIVEN a. B m n PIG. I FIG. 2 the triangle ABC and C, an acute angle. Draw AD perpendicular to CB or CB produced,... | |
 | Joe Garner Estill - 1896 - 214 pages
...the side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of these sides and the projection of the other side upon it. Prove. 5. Two equivalent triangles have a common base and lie on opposite sides of it. Prove that the... | |
 | Joe Garner Estill - 1896 - 186 pages
...the side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of these sides and the projection of the other side upon it. Prove. 5. Two equivalent triangles have a common base and lie on opposite sides of it. Prove that the... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 554 pages
...side opposite tlie obtuse angle is equal to the sum of the squares of the other two sides, plus tivice the product of one of these sides and the projection of the other side upon it. GIVEN — the obtuse-angled triangle ABC with Ft the obtuse angle. Draw AD perpendicular to CB produced,... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry, Modern - 1896 - 276 pages
...the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, plus twice the product of one of these sides and the projection of the other side upon it. B m GIVEN — the obtuse-angled triangle ABC with B the obtuse angle. Draw AD perpendicular to CB produced,... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 570 pages
...of the side opposite an acute angle is equal to the sum of the squares of the other two sides, minus twice the product of one of these sides and the projection of the other side upon it. n FIG. 3 GIVEN the triangle ABC and C, an acute angle. Draw AD perpendicular to CB or CB produced,... | |
 | George Albert Wentworth - Mathematics - 1896 - 68 pages
...343. In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides increased by twice the product of one of those sides and the projection of the other upon that side. 344. I. The sum of the squares of two sides... | |
 | George D. Pettee - Geometry, Modern - 1896 - 272 pages
...the side opposite the obtuse angle is equal to the sum, of the squares of the other two sides plus twice the product of one of these sides and the projection of tJie other upon it. Appl. Prove AC* = CB * + AB * + 2CBxBD Cons. Draw AD -L CB (produced) Dem. CD=CB... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 374 pages
...opposite the obtuse angle is equal to the sum of the squares of the other two sides, plus twice t he product of one of these sides and the projection of the other side upon it. GIVEN — the obtuse-angled triangle ABC with B the obtuse angle. Draw AD perpendicular to CB produced, making... | |
 | Webster Wells - Geometry - 1898 - 250 pages
...of the side opposite an acute angle is equal to the sum of the squares of the other two sides, minus twice the product of one of these sides and the projection of the other side upon it. D B fig. 1. Fig. 2. D Given C an acute Z of A ABC, and CD the projection of side AC upon side CB, produced... | |
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