 | W. V. Wright - Measurement - 1887 - 76 pages
...circumference by 3.14159. When the three sides of a triangle are given, to find the area : From• half the sum of the three sides subtract each side separately. Multiply the half-sum and the three remainders together, and extract the square root of the product. To find the... | |
 | Andrew Jackson Rickoff - 1888 - 464 pages
...rule is sometimes necessary : When the three sides of a triangle are given, to find the area: From half the sum of the three sides subtract each side...the half sum and the three remainders together, and extract the square root of the product. length of each of the two parallel sides of a / A/ The Trapezoid.—Example.... | |
 | Charles Scott Venable - Arithmetic - 1888 - 402 pages
...equals half of the product of either side by the perpendicular to it from the opposite vertex; or, from half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders ; and the square root of the product is the area. III.... | |
 | Thomas A. Rice - Accounting - 1889 - 364 pages
...three sides together. 6. To find area of triangle. — Multiply base by half the altitude. Or, from half the sum of the three sides subtract each side separately ; multiply the half sum by the three remainders, and extract square root of product. 7. To find area of ellipse. — Multiply... | |
 | John Groesbeck - 1891 - 426 pages
...foot. Ans. 63 cents. 447. To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side...the half sum and the three remainders together, and extract the square root of the product. EXAMPLES. 1. What is the area of a triangle whose sides are... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — From half the sum of the three sides subtract each side separately; multiply the half-sum and the three remainders together; the square root of the product is the area. 3. How many... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. RULE. — From half the sum of the three sides subtract each side separately ; multiply the half-sum and the three remainders together; the square root of the product is the area. H. What is... | |
 | Massachusetts - Massachusetts - 1893 - 988 pages
...product of the side and perpendicular, and divide by 160. (ft) When three sides are given. Rule. — From half the sum of the three sides subtract each side...multiply the half sum and the three remainders together; the square root of the product divided by 160 will give the number of acres in the field. (c) When... | |
 | Mines and mineral resources - 1894 - 330 pages
...the sides in the proportion of 3, 4 and 5. The Base x J the perpendicular = area of triangle. From i the sum of the three sides subtract each side separately ; multiply the J sum and the three remainders together, and the square root of the product = the area. HER MAJESTY'S... | |
 | George Washington Hull - Arithmetic - 1895 - 408 pages
...the three sides of a triangle are given and not the altitude, the area can be found as follows : From half the sum of the three sides subtract each side...the half sum and the three remainders together, and extract the square root of the product ; the remit will be the area required. 5. What is the area of... | |
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RULE. — From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area. 
