 | George Bruce Halsted - Measurement - 1881 - 258 pages
...Given the three sides of a triangle, to find the area. Eule ; From half the sum of the three sidles subtract each side separately; multiply the half sum and the three remainders together : the square root of the product will be the area. Formula : A — Vs (s — a) (s — b) (s — c).... | |
 | Daniel W. Fish - Arithmetic - 1883 - 348 pages
...Find the area of a triangle whose base is 20 ft. and each, of the other sides 15 ft RULE. — From half the sum of the three sides subtract each side...multiply the half -sum and the three remainders together ; the square root of the product is the area. 3. Find the area of a triangle whose sides are 25, 36,... | |
 | Euclides - 1884 - 434 pages
...41, 35 = Vs (s - a) (s - b) (s - c); which expression may be put into the form of a rule, thus : From half the sum of the three sides, subtract each side...remainders together, and the square root of the product will be the area.* 1. If from B there be drawn BE j_ AC or AC produced, then BC . CD = AC . CE. 2.... | |
 | William Waterston - 1884 - 314 pages
...then 4fl X 18 = 810 square feet. 6. The three fides of a triangle being given, toßnd the area: From half the sum of the three sides subtract each side...multiply the half sum and the three remainders together; the square root of the product will be the ares. Ex. If the sides be S6, 28, and 30 Inches, we have... | |
 | Colin Arrott R. Browning - 1884 - 274 pages
...area He'Sht = T5T(15) When we know the length of each side, but not the perpendicular. Rule : — From half the sum of the three sides subtract each side...separately ; multiply the half sum and the three remainders continually together, and the square root of this product will be the area of triangle. (16) In a right-angled... | |
 | George Bruce Halsted - Geometry - 1885 - 389 pages
...the area of a triangle. 319 808. Given, the three sides, to find the area of a triangle. RULE. From half the sum of the three sides subtract each side separately ; multiply together the half -sum and the three remainders. The square root of this product is the area. FORMULA.... | |
 | Andrew Jackson Rickoff - Arithmetic - 1886 - 688 pages
...rule is sometimes necessary : When the three sides of a triangle are given, to find the area : From half the sum of the three sides subtract each side...the half sum and the three remainders together, and extract the square root of the product. The Trapezoid. —Example. — Given the length of each of... | |
 | Edward Richard Shaw - 1887 - 488 pages
...244. That which has length and breadth only. 245. Multiply the base by half the altitude. 246. From half the sum of the three sides subtract each side...the half sum and the three remainders together, and extract the square root of the product. 247. Multiply the base by the altitude. 248. Multiply the length... | |
 | Edward Richard Shaw - Examinations - 1887 - 360 pages
...244. That which has length and breadth only. 245. Multiply the base by half the altitude. 246. From half the sum of the three sides subtract each side...the half sum and the three remainders together, and extract the square root of the product. 247. Multiply the base by the altitude. 248. Multiply the length... | |
 | Christian Brothers - Arithmetic - 1888 - 484 pages
...= 468 sq. yd. RULE. — From half the sum of the three sides, subtract each side separately ; then multiply the half sum and the three remainders together; and the square root of the continued product will be the area. ê. Find the area of a triangle whose sides are 63, 60, and 39.... | |
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RULE. — From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area. 
