 | Henry William Jeans - 1873 - 292 pages
...57°.39577— 57°-29577 — 5729577" whence BAC=53° 38' 30", and a;=100xtan. BAC=407-5. PROB. 63. Since the area of a parallelogram is equal to the product of its base by its altitude,* and the area of triangle =£ area of a parallelogram with same base and altitude,... | |
 | Henry W. Jeans - 1873 - 272 pages
...4x57°-29577 57°-29577 5729577 whence BAC=53° 38' 30", and *=100 xtan. BAC=407'5. PEOB. 63. Since the area of a parallelogram is equal to the product of its base by its altitude,* and the area of triangle = J area of a parallelogram with same base and altitude,... | |
 | Charles Davies - 1874 - 464 pages
...lines, because the product is equal to the area of a rectangle constructed with the lines as sides. D E PROPOSITION V. THEOREM. The area of a parallelogram...equal to the product of its base and altitude. Let AB CD be a parallelogram, AB its base, and BE its altitude : then will the area of ABCD be equal to... | |
 | Adrien Marie Legendre - Geometry - 1874 - 500 pages
...continued product of the number of linear units in each of the three lines. Thus, -when we say that the area of a parallelogram is equal to the product of its base and altitude, we mean that the number of superficial units in the parallelogram is equal to the number of linear... | |
 | William Guy Peck - Conic sections - 1876 - 376 pages
...product expresses the area of a rectangle whose adjacent sides are the given lines. PROPOSITION III. THEOREM. The area of a parallelogram is equal to the product of its base and altitude. Let ACDE be a parallelogram; draw AL K_ and CK perpendicular to AC meeting ED, and ED prolonged at L and... | |
 | 1876 - 646 pages
...a triangle divides the opposite side into segments which are proportional to the adjacent sides. 3. The area of a parallelogram is equal to the product of its base and altitude. 4. How do you find the area of a trapezoid ? The areas of similar polygons are to each other in what... | |
 | Alfred Kirk, Henry Holmes Belfield - Arithmetic - 1876 - 220 pages
...annexing to it, in the / manner shown, an equal / triangle, may form a par/ allelogram. 224=. Since the area of a parallelogram is equal to the product of its base and altitude; and since every parallelogram may be divided into two equal triangles having the same base and altitude... | |
 | Aaron Schuyler - Geometry - 1876 - 384 pages
...Then, R : R' : : ab : a'b' (195). But, R = ab, .-. R'^a'b' (ALG... 317, 2). 197. Proposition IV.— Theorem. The area of a parallelogram is equal to the product of it* base by its altitude. Let P denote the area of the Fr — -^— parallelogram ABCD, b its base,... | |
 | William Guy Peck - Arithmetic - 1877 - 430 pages
...its altitude ? Ans. 16 ft. AREA OF A PARALLELOGRAM. 285. It is shown in Geometry (B. 4, P. 3), that the area of a parallelogram is equal to the product of its base and altitude; that is, Area of parallelogram = Base x Altitude. EXAM PLE S. 1. The base of a parallelogram is 14... | |
 | George Albert Wentworth - Geometry - 1877 - 416 pages
...equal to the unit of measure ; and the area of the figure equals 7X4. PROPOSITION IV. THEOREM. 321. The area of a parallelogram is equal to the product of its base and altitude. BE CFB CE F D AD Let AE FD be a parallelogram, AD its base, and С D its altitude. We are to prove... | |
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The area of a parallelogram is equal to the product of its base and altitude. 
