| Edward Brooks - Geometry - 1868 - 284 pages
...cancelling the equal factor in the second couplet of Cor. 1, we have, ABCD : EFGH:: AB : EF. THEOREM II. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, AB its base, and EB its altitude; then will its area be equal to For, at the points... | |
| William Chauvenet - Geometry - 1871 - 380 pages
...is measured by the product of the numerical measures of the lines. PROPOSITION IV.— THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, k the numerical measure of its base AB, h that of its altitude AF; and denote its... | |
| Elias Loomis - Geometry - 1871 - 302 pages
...linear units contained in the base, and the oth«r the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Let ABCD be a parallelogram, AF its altitude, and AB its base ; then is its surface... | |
| Adrien Marie Legendre - Geometry - 1871 - 490 pages
...lines, because the product is equal to the area of a rectangle constructed with the lines as sides. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of it» base and altitude. Let ABCD be a parallelogram, AB its base, and BE its altitude : then will the... | |
| William Chauvenet - Mathematics - 1872 - 382 pages
...lines is measured by the product of the numerical measures of the lines. PROPOSITION IV.—THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, k the numerical measure of its base AB, h that of its altitude AF; and denote its... | |
| William Chauvenet - Geometry - 1872 - 382 pages
...of a number" has been adopted to signify "second power of a number." PROPOSITION IV.—THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let And) be a parallelogram, k the numerical measure of its base AB, h that of its altitude AF; and denote... | |
| William Frothingham Bradbury - Geometry - 1872 - 124 pages
...be neglected. 91 Corollary. The area of a square is the square of one of its sides. THEOREM III. 101 The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ _ F 0 lelogram ABCD ; then the area of / . \7 At A draw the perpendicular... | |
| William Frothingham Bradbury - Geometry - 1872 - 262 pages
...be neglected. 9. CoroUary. The area of a square is the square of one of its sides. THEOREM III. 10, The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ FC lelogram A BCD; then the area of \l '. [~7 ABCD — ADXDF.... | |
| Charles Davies - Geometry - 1872 - 464 pages
...continued product of the number of linear units in each of the three lines. Thus, when we say that the area of a parallelogram is equal to the product of its base and altitude, we mean that the number of superficial units in the parallelogram is equal to the number of linear... | |
| William Frothingham Bradbury - Geometry - 1873 - 132 pages
...neglected. 9, Corollary. The area of a square is the square of one of its sides. THEOREM III. 10« The area of a parallelogram is equal to the product of its base and altitude. ' — 7 -- " - '• — 7 lelogram AB CD ; then the area of j / / Let DF be the altitude of the paral-... | |
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