| Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...whole number of square rods to neres.] Ans. 26 acres 1 r. 25 rods. PROS. ii. — To find the area of a parallelogram, or long square. RULE. Multiply the...by the breadth, and the product will be the area. EXAMPLES. 1. How many square yards of ground are contained in a garden •which is 126 feet long and... | |
| Daniel Adams - Arithmetic - 1849 - 142 pages
...&c. IT 37. The length and breadth of a square or rectangle being given, to find the square contents. RULE. Multiply the length by the breadth, and the product will be the square contents. NOTE. For an analysis of the principles of this and the following rule, see Revised... | |
| Almon Ticknor - Measurement - 1849 - 156 pages
...breadth will make a square foot, &c. .TIMBER MEASURE. To find the area of a board or plank. KULE. — Multiply the length by the breadth, and the product will be the content required. Or, multiply the length by the breadth in inches, and divide the product by 12. When... | |
| Nathan Daboll - Arithmetic - 1850 - 254 pages
...measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product wil) be the area, or superficial content. EXAMPLES. 1. A certain garden, in form of a long square, is 96 fee! long, and 54 wide ; how many square feet of ground are contained in it? Ans. 9(5x54=5.184 square... | |
| John Radford Young - Measurement - 1850 - 294 pages
...find the area of a rectangle from knowing the measures of its sides, that is, its length and breadth. RULE. — Multiply the length by the breadth, and the product will be the area. EXAMPLES. 1 . Required the area of a rectangle whose length is 1 8 feet, and breadth 14 feet. 1 8 lineal... | |
| Daniel Adams - Measurement - 1850 - 144 pages
...&c. ^T ST. The length and breadth of a square or rectangle being give?i, to find the square contents, Multiply the length by the breadth, and the product will be the square contents. NOTE. For an analysis of the principles of this and the following rule, see Revised... | |
| Sir Henry Edward Landor Thuillier - Surveying - 1851 - 826 pages
...• - - «7 ^ 1568160 = 10890 6272640 = 43560 To determine the area of a Rectangular Parallelogram. RULE. — Multiply the length by the breadth and the product •will be the area. EXAMPLES. Suppose the side of a square to be 10 Chs. 48 Lks. what is the area ? Answer, 10 Acr. 3 Rd.... | |
| Chambers W. and R., ltd - 1859 - 344 pages
...&c. — thus, for 6 inches, take the .1 of 1 foot ; and so on. I. To FIND THE AREA OF A BECTANGLE. RULE. — Multiply the length by the breadth, and the product will be the area. Example 1. — What is the area of a rectangle, whose length is 4 feet and breadth 3 feet? 4 X 3 =... | |
| William Keane (gardener.) - 1861 - 252 pages
...a rectangular piece of ground whose length is 16 chains 64 links, and breadth is 7 chains 44 links. Rule : — Multiply the length by the breadth, and the product will be the content. 16-64 7-44 6656 6656 •3 11648 8 10) 123.8016 1C cLaius 64 finks. 12,38016 4 1-52064 40 AR... | |
| Daniel Adams - Arithmetic - 1861 - 452 pages
...row. We multiply the number of squares in one row by the number of rows; C x 3 = 1C square rods, Ans. RULE. — Multiply the length by the breadth, and the product will be the square contents. NOTE 4. — A line 3 times 5 rods long, is a line 15 rods long. Hence the pupil must... | |
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