 | Tobias Ostrander - Measurement - 1833 - 172 pages
...difference and the sum will be the length of the longest side, subtracted leaves the shortest, then multiply the length by the breadth and the product will be the area. EXAMPLES. lelogram. Ans. 30 and 20 chains, the length of the sides required, and the area, 60 acres.... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 pages
...and the gable 1 brick thick. Required the expense of the whole at £5. .16. per rod. BOARD MEASURE. RULE. Multiply the length by the breadth, and the Product will be the answer. (1) If a plank be 17^ inches broad and 29 feet long, what is the content? (2) What is the content... | |
 | George Alfred - Arithmetic - 1834 - 336 pages
...right by Practice Ans. 248 09", and.Duodecimals. PROBLEM 2. To find the area or superficial content of a parallelogram or long square. RULE. , Multiply the length by the breadth, and the product will be tht area or superficial content required. EXAMPLES. 1. What is the superficial content of a plank that... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...which is the answer. TIMBER MEASURE. PROBLEM I. To find the tuperficial content of a board or planfc. RULE. Multiply the length by the breadth, and the product will be the area. Nate. When the plank is broader at one end than at the other, add both ends together, and take half... | |
 | Tobias Ostrander - Measurement - 1834 - 182 pages
...difference and the sum will be the length of the longest side, subtracted leaves the shortest, then multiply the length by the breadth and the product will be the area. EXAMPLES. i 1. The sum of the two adjacent sides of a rectangular parallelogram is 50 chains, and the... | |
 | Nathan Daboll - Arithmetic - 1835 - 260 pages
...— 160 square rods make an acre. Therefore, 26x26=676 sq. rods, and 676^-160=4 «. 36 r. the Answer. ART. 2. To measure a parallelogram, or long square....content. EXAMPLES. 1. A certain garden, in form of along square, is 96 feet long, and 54 wide ; how many square feet of ground arc contained in it 1 Ans.... | |
 | Education - 1835 - 496 pages
...V imrallelogram is a four-sided right-angled figure, longer than broad. TO MEASURE A PARALLELOGRAM. Multiply the length by the breadth, and the product will be the area. .V. How many feet does a floor in the form of a parallelogram measure, wluimi length is 24 feet, 6... | |
 | William Ruger - Arithmetic - 1836 - 274 pages
...and 20ft. long? Ans, 80yds. NOTE. — To obtain the surface of a plane, as a floor, field., if-e.- Multiply the length by the breadth, and the product will be the surface; then as the number of square feet in a yard of the carpeting which is 4,5 feet, is to one... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...Therefore, 26 X 26 =676 Sq. rods, and 676-M60=4a, 36r. the Answer. ART. 2. To measure a parallellograra, or long square. RULE. Multiply the length by the breadth,...A certain garden, in form of a long square, is 96 11. long, and 54 wide ; how many square feet of ground aré contained in it? Ans. 96X54=5184 square... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 290 pages
...which is the answer. TIMBER MEASURE. PROBLEM I. To find the superficial content of a board or plank. RULE. Multiply the length by the breadth, and the product will, be the area. BY THE CARPENTER'S RULE. Set 1 2 on B, to the breadth in inches on A ; then against the length in feet,... | |
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To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. 
