 | George Roberts Perkins - Arithmetic - 1849 - 344 pages
...the first term, the last term, and the number of terms, to find the common difference, we have this RULE, Divide the difference of the extremes by the number of terms, less one. EXAMPLES. 1. The first term of an arithmetical progression is 5, the last term is 176, and the number... | |
 | Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...CASE n. • ' The first term, last term, and number of terms given, to f,nd the common difference. RULE. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference. EXAMPLES. 1. A man bought 17 yards of cloth in arithmetical... | |
 | James Bates Thomson - Arithmetic - 1849 - 438 pages
...12 hours? 604. To find the common difference, when the extremes and the number of terms are given. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference required. OBS. The truth of this rule is manifest... | |
 | Benjamin Greenleaf - Arithmetic - 1850 - 368 pages
...differences, the quotient will be the common difference. Thus 16 -5- 8 = 2 is the common difference. RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. 1. The extremes are 3 and 45, and the number of terms is 22. What is the... | |
 | George Roberts Perkins - Arithmetic - 1850 - 356 pages
...the first term, the last term, and the number of terms, to find the common difference, we have this RULE. Divide the difference of the extremes by the number of terms, less one. EXAMPLES. 1 . The first term of an arithmetical progression is 5, the last term is 176, and the number... | |
 | Charles Guilford Burnham - 1850 - 350 pages
...238. — When the extremes and number of terms are given, to find the common difference, we have this RULE. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference. 7. If the first term of a series be 3, the last... | |
 | Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...•*- 5= 5 years, the common difference. A. 5 years. 1 1 . Hence, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will oe the common difference. 12. If the extremes be 3 and 23, and the number... | |
 | Daniel Leach - Arithmetic - 1851 - 280 pages
...found. 312. To find the common difference when the two extremes and the number of terms are. known,-— RULE. Divide the difference of the extremes by the..., and the quotient will be the common difference. This rule may be represented by the formula, thus ; Let a— .first term, d —common difference, ^last... | |
 | Benjamin Greenleaf - 1851 - 332 pages
...quotient will be the common difference. Thus, 27 -fr- 9 = 3, the common difference. Hence the following RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. • EXAMPLES FOR PRACTICE. 1. The extremes of a series are 3 and 35, and... | |
 | Arithmetic - 1851 - 260 pages
...and the last, or fifty-second, payment $1236 ? Ans. 32448. NOTE &. —To find the common difference, divide the difference of the extremes by the number of terms, less one. EXAMPLES. 1 The ages of 8 boys form an arithmetical series-— the youngest is 4 years old and the... | |
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RULE. Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. 
