 | George Edward Atwood - Arithmetic - 1894 - 396 pages
...and write its square root for the first figure of the root. Subtract this square from the left-hand period, and to the remainder annex the next period for a dividend. Double the root already found for a partial divisor. Divide the dividend, omitting the right-hand figure,... | |
 | Bothwell Graham - Arithmetic - 1895 - 240 pages
...of a quotient at the right of the number. Subtract the square of this root figure from the lefl-hand period, and to the remainder annex the next period for a dividend. Take twice the figure of the root found for a trial divisor; divide the dividend, omitting the last... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...root at tlie right of the given number. 3. Subtract the square of this root figure from the left-hand period, and to the remainder annex the next period for a dividend. £. Double the root already found for a trial divisor, and omitting the right-hand figure of the dividend,... | |
 | George Edward Atwood - Arithmetic - 1899 - 392 pages
...period, and write its cube root for the jirst figure of the root. Subtract this cube from the left-hand period, and to the remainder annex the next period for a. dividend. Square the root already found, multiply the square by 8, and to the. product annex two ciphers for... | |
 | Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...the given number into periods of three figures each. root. Subtract the cube of this number from the period, and to the remainder annex the next period for a dividend. 3. Square the part of the root found, multiply the product by 300, and write the result ou the left... | |
 | Léon Stefflre - Arithmetic - 1902 - 230 pages
...period thus formed and place it under, and its root over, such period ; 8. Subtract this cube from said period and to the remainder annex the next period for a dividend, ie, carry said remainder to the next period; e. Multiply the square of the part of the root found by... | |
 | Edward Gideon - 1902 - 272 pages
...root for the first figure of the required root. Subtract the cube of this figure from the left-hand period, and to the remainder annex the next period, for a dividend. III. Multiply the square of the root already found, regarded as tens, by 3; find how often it is contained... | |
 | Jacob Henry Minick, Clement Carrington Gaines - Business mathematics - 1904 - 412 pages
...write it as the first figure of the root. Square this root and subtract the result from the left-hand period, and to the remainder annex the next period for a dividend. Double the root found for a trial divisor ; divide the dividend, omitting the right-hand figure, by... | |
 | Benjamin Franklin Sisk - Arithmetic - 1905 - 224 pages
...left-hand period and write its root for the first figure in the root. 3. Subtract the cube from the period, and to the remainder annex the next period for a dividend. 4. For a trial divisor, write three times the square of the root found, considered as tens. 5. Divide,... | |
 | Stephen Roper - Electrical engineering - 1907 - 878 pages
...first figure in the required root. From that period subtree: the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by three hundred for s 'trial divisor, and see how often it is contained in the dividend, and... | |
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Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 
