 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend, and place the (/uotient, usually... | |
 | James Stewart Eaton - Arithmetic - 1857 - 376 pages
...cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by 3 for a TRIAL DIVISOR ; divide... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor, and see how often it is contained... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor, and see how often it is contained... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and place the <fuotient, usually... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 456 pages
...jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior, and see how often it is contained... | |
 | Emerson Elbridge White - Arithmetic (Commercial), 1861 - 1861 - 348 pages
...right as the highest order of the root. 3. Subtract the square of the root figure from the left hand period, and to the remainder annex the next period for a dividend. 4. Double the part of the root already found for a trial divisor, and see how many times it is contained... | |
 | James Stewart Eaton - 1862 - 320 pages
...cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by § for a TRIAL DIVISOTJ ;... | |
 | George Augustus Walton - Arithmetic - 1864 - 376 pages
...first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide the dividend by the trial divisor,... | |
 | George Augustus Walton - Arithmetic - 1864 - 364 pages
...first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide the dividend by the trial divisor,... | |
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Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 
