 Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required.  Arithmetic. [With] Key - Page 132by Robert Goodacre - 1839Full view - About this book
 | Mathematics - 1801 - 446 pages
...mentioned. 3. Multiply the second and third numbers together, and divide.* the product by the first, and the quotient will be the answer to the question, in the same denomination you left the second number in ; which may be brought into any other denomination required. EXAMPLE.... | |
 | Charles Vyse - Arithmetic - 1806 - 342 pages
...mentioned. 3. Multiply the second and third Terms together, and divide that Product by the first. ' The Quotient will be the Answer to the Question, in the same Denomination or Name you left your second Term in. 4. If there happens to be a Remainder after the Division, reduce... | |
 | Samuel Webber - Arithmetic - 1812 - 260 pages
...mentioned. 3. Multiply the second and third numbers together, and divide the product by the first, and the quotient will be the answer to the question, in the same denomination you left the second number in ; which may be brought into any other denoroina- . don required. Write... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...it. 3. Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. Tlie method... | |
 | Charles Vyse - Arithmetic - 1815 - 340 pages
...name mentioned. 3. Multiply the second ^nd third terms together, and divide that product by the «rst. The quotient will be the answer to the question, in the same denomination you left your second term in. 4. If there happen to be a remainder after the division, reduce it into... | |
 | Nathan Daboll - Arithmetic - 1823 - 262 pages
...it. 3. Multiply the second and third terms together, and divide their product by the first term .• the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. fhe method... | |
 | John Dozell - Arithmetic - 1827 - 190 pages
...term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination as you left the second number in. If there happen to be a remainder after the Division, reduce it into... | |
 | William Slocomb - 1828 - 160 pages
...mentioned in it. e 3. Multiply the second and third terms together, and divide their product by the first; the quotient will be the answer to the question, in the same denomination in which you left the second term, and may be brought into any other denomination required. Continue... | |
 | Nathan Daboll - Arithmetic - 1828 - 262 pages
...it. 3. Multiply the second and third terms-togethicr, and divide th«ir product by the first term l the quotient, will be the answer to the question, in the same denemination you left the second term in, which may be brought into any other denomination required..... | |
 | Thomas Smith (of Liverpool.) - 1830 - 282 pages
...all the terms together that are not marked, and to divide the product by those that are marked ," and the quotient will be the answer to the question, in the same denomination as that in which you left the second term." Precepts without examples, are of little avail, whether it... | |
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