 Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required.  Arithmetic. [With] Key - Page 132by Robert Goodacre - 1839Full view - About this book
 | Thomas Conkling (W.) - Arithmetic - 1831 - 302 pages
...Question. 1. Multiply the second and third terms together, and divide the product by the first term- The quotient will be the answer to the question in the same name or denomination the second term was left in. This you must remember; for, by it, you can determine... | |
 | Francis Walkingame - 1832 - 224 pages
...term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination you left the second number in. EXAMPLES. 1. If 1 Ib. of sugar cost 4Jrf. what cost 54 Ib. *?4{ ;tw... | |
 | Francis Walkingame - 1835 - 270 pages
...mentioned in it, then multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination the third term was reduced to, and must be reduced to the highest denomination it admits of. Note.... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...mentioned in it. 3. Multiplythesecond and third terms together and divide their product by the first term; the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. The method... | |
 | Roswell Chamberlain Smith - 1837 - 306 pages
...denomination mentioned in it. 3. Divide the product of the second and third terms by the first term ; th« quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...denomination mentioned. Multiply the second and third terms together, and divide the product by the first : the quotient will be the answer to the question, in the same denomination you left the third term in. Proof. — Invert the question ; that is, place the answer for the first... | |
 | Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...denomination mentioned in it. 3. Divide the product of the second and third terms by the first term ; the quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...denomination mentioned in it. 3. Divide the product of the second and third terms by the jirst term ; the quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | John Darby (teacher of mathematics.) - 1843 - 236 pages
...stated; then multiply the first and second terms together, and divide the product by the third, and the quotient will be the answer to the question in the same denomination the second term was left in. Or, by the general rule, given in the Rule of Three Direct. EXAMPLES.... | |
 | Alfred Crowquill - Arithmetic - 1843 - 156 pages
...term mentioned. Multiply the second and third numbers together, and divide the product by the first; the quotient will be the answer to the question in the same denomination you left the second number in. SINGLE RULE OF THREE. EXAMPLES. If 1 lb. of sugar cost 4|d., what cost... | |
| |
