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" Fig. 1. 2. To find the area of a triangle: Rule — Multiply the base by half the altitude. "
Cyclopedia of Architecture, Carpentry and Building: Carpentry. Stair ... - Page 230
1909
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New American Practical Navigator

Nautical astronomy - 1821 - 708 pages
...feet by the perpendicular 15 feet; the product 460 is tlic •. / area in square feet. PROBLEM II. To find the area of a Triangle. RULE. Multiply the base by half the perpendicular height, and the product will be the area required. A a 178 EXAMPLE. Given the base AC...
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A Treatise on Practical Gauging

Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...given superficies 1 6 to find the diameter of a circle, when the area is given ......... 17 ro End the hypothenuse of a right-angled triangle, when the base and perpendicular are given ................ .. ........ 17 -i.ven the hypothenuse of a right-angled triangle, and either...
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The Operative Mechanic, and British Machinist: Being a Practical ..., Volume 1

John Nicholson - Machinery - 1825 - 822 pages
...the area of a rhombus, whose length is 6 chains, and perpendicular height 5. — 6 5 Ansr. 30 Prol. 2. To find the Area of a Triangle. Rule ] . Multiply the base by the perpendicular height, and half the product will be the area. Rule 2. When the three sides only...
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A Treatise on the New Method of Land Surveying, with the Improved Plan of ...

Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...breadth AD 310 links, Dr 640 310 6400 1920 1.98400 4 3.93G00 40 37.44000 Ans. IA. 3n. 37p. PROBLEM 2. To find the Area of a Triangle. RULE. Multiply the base by the perpendicular, and half the product will be the area. RULE II. Add the three sides together, and...
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A Compendium of Mechanics; Or; Text Book for Engineers, Mill-wrights ...

Robert Brunton - Mechanical engineering - 1828 - 222 pages
...Rhomboid, the length AB being 7, the perpendicular B c being 4? 7 X 4 = 28 area of Rhomboid. PROBLEM II. To find the area of a Triangle. RULE. Multiply the base by the perpendicular height, and take half the product for the area. EXAMPLE. What is the area of a Triangle,...
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An Introduction to Mensuration and Practical Geometry

John Bonnycastle - Geometry - 1829 - 256 pages
...of a rectangular board, whose length is 12£ feet, and breadth 9 inches. Ans. 9f feet. PROBLEM II. To find the area of a triangle. RULE.* Multiply the base by the perpendicular height, and half the product will be the area. Note. — The perpendicular height...
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A treatise on practical geometry, mensuration, conic sections, gauging, and ...

Ireland commissioners of nat. educ - 1834 - 370 pages
...whose length is 3 yards, and perpendicular height 2 feet 3 inches ? Ans. 20 feet 3 inches, PROBLEM IV. To find the area of a Triangle. RULE. Multiply the base by the perpendicular height, and divide the product by two for the area.f * Demonstration. Because the...
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A Treatise on Mensuration for the Use of Schools

Commissioners of National Education in Ireland - Measurement - 1837 - 290 pages
...whose length is 3 yards, and perpendicular height 2 feet 3 inches ? Ana. 20 feet 3 inches. PROBLEM IV. To find the area of a Triangle. RULE. Multiply the base by the perpendicular height, and ' divide the product by two for the area.f 1. The base of a triangle...
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The National Arithmetic, on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...base of a rhombus being 12 feet, and its height 8 feet. Required the area. Ans. 96 feet. PROBLEM m. To find the area of a triangle. RULE. — Multiply the base by half the perpendicular height ; or add the three sides together; then take half of that sum, and out of it subtract...
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The National Arithmetic ...: Combining the Analytic and Synthetic Methods ...

Benjamin Greenleaf - Arithmetic - 1841 - 334 pages
...base of a rhombus being 12 feet, and its height 8 feet. Required the area. Ans. 96 feet. PROBLEM III. To find the area of a triangle. RULE. — Multiply the base by half the perpendicular height; or add the three sides together; then take half of that sum, and out of it subtract...
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