| Benjamin Greenleaf - Arithmetic - 1842 - 184 pages
...breadth, and the product is the superficial contents. 2. To find the area of a rhombus or a rhomboid. 3. To find the area of a triangle. RULE. Multiply the base by half the perpendicular height; or, add the three sides together ; then take half of that sum, and out of it... | |
| Osman Call - Arithmetic - 1842 - 210 pages
...area. What is the area of a rhomboid, the length being 7, and the perpendicular being 4 ? Ans. 28. TO FIND THE AREA OF A TRIANGLE. RULE. — Multiply the base by the perpendicular height, and take half the product for the area. What is the area of a triangle, the... | |
| Benjamin Greenleaf - Arithmetic - 1844 - 204 pages
...area of a rhombus or rhomboid. RULE. Multiply the length of the bose by the perpendicular height. 3. To find the area of a triangle. RULE. Multiply the base by half the perpendicular height ; or, add the three sides together ; then take half of that sum, and out of it... | |
| Benjamin Greenleaf - Arithmetic - 1844 - 208 pages
...area of a rhombus or rhomboid. RULE. Multiply the length of the base by the perpendicular height. 3. To find the area of a triangle. RULE. Multiply the base by half the perpendicular height ; or, add the three sides together ; then take half of that sum, and out of it... | |
| Nathan Scholfield - 1845 - 894 pages
...breadth of a rhomboid, whose area = 65 J square feet, the length 12J feet. Ans. 5 ft. 4 in. PROBLEM u. To find the area of a triangle. RULE. — Multiply the base by the perpendicular height, and take half ihe product for the area, (Prop. VIII. B. IV.) Schol. — If... | |
| Charles Davies - Geometrical drawing - 1846 - 254 pages
...is the area of a triangle whose sides are 24, 36, and 48 yards? Ans. 418.282 sg. yds. 28. How do you find the hypothenuse of a right-angled triangle when the base and perpendicular are known ? 1st. Square each of the sides separately. 2d. Add the squares together. 3d. Extract the square root... | |
| James Robinson (of Boston.) - 1847 - 304 pages
...measuring unit, and the area of any figure is the number of times it contains the measuring unit. Art. 192. To FIND THE AREA OF A TRIANGLE. RULE. Multiply the base by the altitude or perpendicular height ; divide the product by 2 ; the quotient will be the area. Or,... | |
| John Bonnycastle - Geometry - 1848 - 320 pages
...area of a rectangular board, whose length is 12J feet, and breadth 9 inches. Ans. 9f feet. PROBLEM II. To find the area of a triangle. RULE.* Multiply the base by the perpendicular height, and half the product will be the area. Note. — The perpendicular height... | |
| Benjamin Greenleaf - Arithmetic - 1850 - 368 pages
...base of a rhombus being 12 feet, and its height 8 feet, required the area. Ans. 96 feet. PROBLEM m. To find the area of a triangle. RULE. — Multiply the base by half the perpendicular height; or, add the three sides together ; then take half of that sum, and out of it... | |
| Ezra S. Winslow - Business mathematics - 1853 - 264 pages
...distance from the side FG to the side HI being 8 feet? 12 X 8 = 96 square feet. Ans. OF TRIANGLES. To find the area of a triangle. RULE. — Multiply the base by half the perpendicular height, or the perpendicular height by half the base, and the product is the area. Or,... | |
| |