| George Albert Wentworth - Geometry, Plane - 1899 - 272 pages
...COR. 7. In an equiangular triangle, each angle is one third of two right angles, or 60°. 137. COR. 8. **An exterior angle of a triangle is equal to the sum of the two opposite interior angles,** and therefore greater than either of them. PROPOSITION XIX. THEOREM. 138. Tlie sum of two sides of... | |
| Webster Wells - Geometry - 1899 - 420 pages
...Cor. I. It follows from the above demonstration that Z BCD = Z ECD + Z J3OS = Z .4 + Z 5 ; hence 1. **An exterior angle of a triangle is equal to the sum of the two opposite interior angles.** 2. An exterior angle of a triangle is greater than either of the opposite interior angles. RECTILINEAR... | |
| William James Milne - Geometry, Modern - 1899 - 258 pages
...acute angle of one are equal to a side and an acute angle of the ot^er, each to each. 115. Cor. V. Any **exterior angle of a triangle is equal to the sum of the two opposite interior angles.** 1. What interior angle is equal to Z t' ? Why ? 2. What interior angle is equal to Z s' ? Why ? 3.... | |
| Webster Wells - Geometry - 1899 - 450 pages
...85. Cor. I. It follows from the above demonstration that ZBCD = ZECD + ZBCE = ZA + ZB; hence 1. .471 **exterior angle of a triangle is equal to the sum of the two opposite interior angles.** 2. An exterior angle of a triangle is greater than either of the opposite interior angles. 87. Cor.... | |
| William James Milne - Geometry - 1899 - 404 pages
...angle of one are equal to a side and an acute angle of the ofoer, each to each. " 115. Cor. V. Any **exterior angle of a triangle is equal to the sum of the two opposite interior angles.** 1. What interior angle is equal to Z t' ? Why ? 2. What interior angle is equal to Z s' ? Why ? 3.... | |
| Edward Brooks - 1901 - 278 pages
...angle of the other, the other acute angles are equal. TRIANGLES. PROPOSITION XVIII. — THEOREM. The **exterior angle of a triangle is equal to the sum of the two opposite interior angles.** Given. — Let ABC be any triangle, and CBD be its exterior angle. To Prove. — Then we are to prove... | |
| Arthur Schultze - 1901 - 260 pages
...equal respectively to the hypotenuse and an acute angle of the other. PROPOSITION XIII. THEOREM 100. **An exterior angle of a triangle is equal to the sum of** the two remote interior angles. f / B CD Hyp. Z ACD is an exterior angle of A ABG. To prove Z ACD =... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...92. The altitudes upon the arms of an isosceles triangle are equal. PROPOSITION XIII. THEOREM 100. **An exterior angle of a triangle is equal to the sum of** the two remote interior angles. , B • CD Hyp. ZACD is an exterior angle of A ABC. To prove Z ACD... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 390 pages
...equal respectively to the hypotenuse and an acute angle of the other. PROPOSITION XIII. THEOREM 100. **An exterior angle of a triangle is equal to the sum of** the two remote interior cuujles. BGD Hyp. Z ACD is an exterior angle of A ABC. To prove Z ACD = ZA... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...equal respectively to the hypotenuse and an acute angle of the other. PROPOSITION XIII. THEOREM 100. **An exterior angle of a triangle is equal to the sum of** the two remote interior angles. B CD Hyp. Z ACD is an exterior angle of A ABC. To prove Z ACD = HIMT.... | |
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