| James William Nicholson - Arithmetic - 1889 - 408 pages
...contained times in $114.60, equal to $375. Formula. — Principal = Interest -h (Rate X No. of Years). RULE. — Divide the given interest by the interest of $1 for the given time and rate; the quotient -will express the number of dollars in the principal. If the amount is given... | |
| Warren H. Sadler, William Russell Will - Business mathematics - 1890 - 316 pages
...($8.10) is 150 times the interest of $1 ($.054) the principal of the given interest must be 150 times $1. RULE. — Divide the given interest by the interest of $1 for the given time and at the given rate. NOTE 1. — To find the interest of $1, divide the days regarded as cents by... | |
| Warren H. Sadler, William Russell Will - Business mathematics - 1890 - 312 pages
...be 150 times $1. 8.100-=-.054 = $150, Ans. (360-i-8 = 45) produces .054 as the rate RULE.—Divide the given interest by the interest of $1 for the given time and at the given rate. NOTE 1.—To find the interest of $1, divide the days regarded as cents by the... | |
| Wm. M. Peck - 1894 - 310 pages
....06. ' " " $1. " 3 months at 5% is .015. " " $1. " 15 days at 6$ is .0025. The sum of these, .0775, is the interest of $1. for the given time at the given rate, and, since the interest of $1. is $0.0775, the interest of $150 is 150 times that sum, or $11.625.... | |
| George Washington Hull - Arithmetic - 1895 - 408 pages
...as Int. of $1 = $.lo2 152 {s contained times iu 30.40, $30.40 -*- .152 = $200, Aus. which is $200. RULE. Divide the given interest by the interest of $1 for the given time and rate. What principal at interest will gain — 2. $105.60 in 3 yr. 8 mo. at 6% ? 3. $11.76 in 4... | |
| Edward Brooks - Arithmetic - 1895 - 424 pages
...dollars as $.21 are contained $136.50 »6,.Q times in $136.50, which is $650. Hence the .21 following Rule. — Divide the given interest by the interest of $1 for the given rate and time, or divide the amount by the amount of $1. What principal will 4. Amount to $1200.50... | |
| William Seneca Sutton - 1896 - 342 pages
...da. at 1% ? Ans. $ 1,080. 12. $ 123 in 3 yr. 5 mo. at 8% ? Ans. $450. 254. To find the Principal : Divide the given interest by the interest of $1 for the given time at the given rate; multiply $1 by the quotient. FORMULAS. To find the Time. 255. To find the time is to find the time... | |
| Charles Edward White - Arithmetic - 1897 - 312 pages
...interest, it will take as many dollars to gain $60 interest as $.24 is contained times in $60, or $250. Rule. — Divide the given interest by the interest of $1 for the given time and rate. 2. What principal at 6% will amount to $310 in 4 years ? 3. What sum invested at 5% will... | |
| Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...would require as many dollars to produce $36 interest as $0.096 is contained times in $36, = $375. RULE. Divide the given interest by the interest of $1 for the given time at the given rate. Find the principal in the following: 1. Interest yTime mo. da. Rate Interest yTime mo. da. Rate 2.... | |
| Charles E. Sayward - Business mathematics - 1908 - 188 pages
...time draft. RULE. — Find the cost of a one-dollar sight draft, as by Rule, and from this subtract the interest of $1 for the given time at the given rate. 184. To find the cost or selling price of a draft for any amount. RULE. — Find the cost of a one-dollar... | |
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