 | John Bonnycastle - Geometry - 1829 - 256 pages
...15, required the length of the arc. Ans. 53.5800. PROBLEM XI. To find thf area of a circle. RULE I.* Multiply half the circumference by half the diameter, and the product will be the area. * Demon. A circle may be considered as a regular polygon of an infinite number of sides, the circumference... | |
 | William Templeton (engineer.) - 1833 - 224 pages
...equal to the radius. 6. — The area of a circle is to the square of the diameter as .7854 to 1 ; or, Multiply half the circumference by half the diameter, and the product will be the area. EXAMPLE 1. — Required the area of a circle, the diameter being 30.5. 30.5* x .7854 = 730.618350,... | |
 | John Bennett (Engineer) - 1833 - 488 pages
...PROBLEM XI. 24. To find the area of a circle, whose diameter and circumference are given. RULES. 1. Multiply half the circumference, by half the diameter, and the product will express the area. Or, 2. Multiply the circumference by the diameter, and a fourth part of the product... | |
 | Education - 1835 - 496 pages
...circumference, and is the greatest space that can be inclosed under one line. TO FIND THE AREA OF A CIRCLE. Multiply half the circumference by half the diameter, and the product will be the area. The diameter of a circle being given to find the circumference. As 7 : 22: : so is the diameter to... | |
 | William Ruger - Arithmetic - 1836 - 274 pages
...£237 10s. id. To find the area of a circle, the circumference and diam'eter being given. RULE. — Multiply half the circumference by half the diameter, and the product will be the area. Or multiply the whole circumference by the whole diameter, and one fourth of the product will be the... | |
 | Luther Ainsworth - Arithmetic - 1837 - 298 pages
...Q. Having the circumference and diameter of a circle given, by what RULE do you find its area ? A. Multiply half the circumference by half the diameter, and the product will be the area. Q. If the diameter alone be given, how can you find [the area, without finding the circumference ?... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 pages
...62.832 X .31831 = 20 as before. The area of a circle is to the square of the diameter as .7854 to 1 ; or multiply half the circumference by half the diameter and the product will be the area. Required the area of a circle the diameter being 30.5. 30.52 X'7854 = 730.618350, the area required.... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...circle given, to find the area ; or the area given, to find the diameter or circumference. RULE. 1. Multiply half the circumference by half the diameter, and the product will be the area. Or multiply the square of the diameter by .7854, and the product will be the area. Or multiply the... | |
 | Abraham Crocker - 1841 - 486 pages
...diameter, and m the multiplying decimal -7854. RULE II. When the Diameter and Circumference are both given. Multiply half the circumference by half the diameter, and the product will be the area. Or, multiply the whole circumference by the whole diameter, and divide the product by 4 ; the quotient... | |
 | John Bonnycastle - Geometry - 1848 - 320 pages
...15, required the length of the arc. Ans. 53.5800, PROBLEM XL To find the area of a circle. RULE I.* Multiply half the circumference by half the diameter, and the product will be the area. * Demon. A circle may lx- considered as a regular polygon of an infinite number of sides, the circumference... | |
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Multiply half the circumference by half the diameter, and the product will be the area. Or, divide the product of the whole circumference and diameter -by 4, and the quotient will be the area. 2. Multiply the square of the diameter by .7854, and the product... 
