 | Webster Wells - Geometry - 1894 - 398 pages
...are equal.] (§66.) But, BH + Gif > BG. PROPOSITION XXIX. THEOREM. 90. (Converse of Prop. XXVIII.) If two triangles have two sides of one equal respectively to two shies of the other, but the third side of the first greater than thk third side of the second, the... | |
 | Webster Wells - Geometry - 1894 - 400 pages
...50.) Whence, the point A falls at D. PROPOSITION XXVIII. THEOREM. 89. If two triangles have two aides of one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, the third side of the first... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 276 pages
...BC'<BX+XC. Or BC'<BC. QED PROPOSITION XXVI. THEOREM 93. If two triangles have two sides of one equal to two sides of the other but the third side of the first greater than the third side of the second, then the angle opposite the third side of the first is greater than the angle opposite the third side... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 276 pages
...Proposition XXIV. does it matter in what order the sides are arranged ? PROPOSITION XXV. THEOREM 92, If two triangles have two sides of one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry, Modern - 1896 - 276 pages
...two sides and the included angle respectively equal are equal.] UA<A' then would .#£.<£' <7. §92 [If two triangles have two sides of one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 554 pages
...A. To PROVE angle SAC<_ angle SAB. Take AB = AC and draw SC and SB. Then the triangles SAC and SAB have two sides of one equal respectively to two sides of the other. But the third side SC of one is less than the third side SB of the other. § 5 36 Therefore angle SA C< angle SAB. §... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 570 pages
...BC'<BX+XC. Or BC'<BC. QED PROPOSITION XXVI. THEOREM 93. If two triangles have two sides of one equal to two sides of the other but the third side of the first greater than thc third side of the second, then the angle opposite the third side of the first is greater than the... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 574 pages
...through A, To PROVE angle SAC<^ angle SAB. Take AB^ACznd draw SC and SB. Then the triangles SAC and SAB have two sides of one equal respectively to two sides of the other. But the third side SC of one is less than the third side 5.5 of the other. § 536 Therefore angle S^C<angle SAB. §93... | |
 | Henry W. Keigwin - Geometry - 1897 - 254 pages
...3, page 23, using §§ 73 und 77a. 2. Restate 8 76a. PROPOSITION XIII. THEOREM. 78. If two trianyles have two sides of one equal respectively to two sides of the oiJier, but the included angle of the first greater than the included angle of the second, then the... | |
 | Arthur A. Dodd, B. Thomas Chace - Geometry - 1898 - 490 pages
...lines are cut by a third so as to make the alternate interior angles equal, the two lines are parallel. 2. If two triangles have two sides of one equal respectively to two sides of the other, but the included angle ot the first greater than the included angle of the second, the third side of the first... | |
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... if two triangles have two sides of one equal, respectively, to two sides of the other... 
