 | Alan Sanders - Geometry - 1903 - 392 pages
...in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY I. The area of any parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD, meeting... | |
 | Alan Sanders - Geometry - 1903 - 396 pages
...in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY I. The area of any parallelogram is equal to the product of its base and altitude. Let A BCD be any parallelogram BE C and DE be its altitude. r To Prove ABCD = AD x DE. Proof. Draw AF _L... | |
 | Fletcher Durell - Geometry, Plane - 1904 - 382 pages
...area of a rectangle 8 yds. long and 5 ft. wide. BOOK IV. PLANE GEOMETRY PROPOSITION IV. THEOREM 385. The area of a parallelogram is equal to the product of its base by its altitude. KB FC Given the ZZ7 ABCD with the base AD (denoted by 6) and the altitude DF... | |
 | Fletcher Durell - Geometry - 1911 - 553 pages
...Find, in square feet, the area of a rectangle 8 yds. long and 5 ft. wide. PROPOSITION IV. THEOREM 385. The area of a parallelogram is. equal to the product of its base by its altitude. K__B__ pa A b D Given the ZZ7 ABCD with the base AD (denoted by b) and the altitude... | |
 | Fletcher Durell - Geometry, Solid - 1904 - 232 pages
...side. BOOK IV. 383. The area of a rectangle is equal to the product of its base by its altitude. 385. The area of a parallelogram is equal to the product of its base by its altitude. 389. The area of a triangle is equal to one-half the product of its base by its... | |
 | George Albert Wentworth - Geometry - 1904 - 496 pages
...evident by dividing the figure into squares, each BOOK IV. PLANE GEOMETRY. PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. CF CE A b DA b D Let AEFD be a parallelogram, b its base, and a its altitude.... | |
 | Walter Burton Ford, Earle Raymond Hedrick - Geometry, Modern - 1913 - 272 pages
...triangles. Find the area of each of these triangles. Ans. 15 sq. in. AREAS [IV, ยง 186 186. Theorem I. The area of a parallelogram is equal to the product of its base by its altitude. F_ GD G Given the parallelogram ABCD with b its base and a its altitude. To prove... | |
 | George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 496 pages
...wide a road is cut 4 rd. wide. How many acres are cut off for the road? PROPOSITION IV. THEOREM 322. The area of a parallelogram is equal to the product of its base by its altitude. A b BA b B Given the parallelogram ABCD, with base b and altitude a. To prove... | |
 | William James Milne - Arithmetic - 1914 - 524 pages
...resulting figure will be a rectangle of the same area, base, and altitude as the BASE parallelogram. The area of a parallelogram is equal to the product of its base and altitude, expressed in like units. ' ' " and Written Exercises Estimate results mentally before solving. Find... | |
 | George E. Mercer, Mabel Bonsall - Arithmetic - 1914 - 324 pages
...should be given practice in drawing them until the mention of a name calls forth an appropriate drawing. The area of a parallelogram is equal to the product of its base and altitude. The base and altitude must be expressed in units of the same kind. The diagonal of a parallelogram... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
