| Charles Reiner - Geometry - 1837 - 254 pages
...angles of the one is equal to the sum of the remaining two angles of the other. 2. If two triangles have two angles of the one equal to two angles of the other, each to each, the third angle of the one is equal to the third angle of the other ; that is, the triangles are equiangular.... | |
| Euclides - Euclid's Elements - 1837 - 112 pages
...be > Z EOF. PROPOSITION XXVI. (Argument ad absurdum). Theorem. If two triangles have two angles of one equal to two angles of the other, each to each, and one side equal to one side; viz., either the sides adjacent to the equal angles, or opposite to the equal angles... | |
| A. Bell - Conic sections - 1837 - 180 pages
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore two angles of the one equal to two angles of the other, and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
| William Whewell - 1837 - 226 pages
...therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the triangles have two angles of the one equal to two angles of the other ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is,... | |
| Euclid, James Thomson - Geometry - 1837 - 410 pages
...equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| Andrew Bell - Euclid's Elements - 1837 - 290 pages
...the angles GMK, GMN, are both right angles by construction ; wherefore the triangles GMK, GMN, have two angles of the one equal to two angles of the other, and they have also the side GM common ; therefore they arc equal, and the side KM is equal to the side... | |
| Euclides - 1838 - 264 pages
...right angle FCK is equal to the right angle FCL ; therefore, in the two triangles FKC, FLC, there are two angles of the one equal to two angles of the other, each to each ; and the side FC, which is adjacent to the equal angles in each, is common to both ; therefore «„ , the... | |
| Robert Simson - Geometry - 1838 - 434 pages
...by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each is common to both ; therefore... | |
| Thomas Kerigan - Nautical astronomy - 1838 - 804 pages
...the angle BCD, by the aforesaid proposition. And because the two triangles ADF and BCF have, thus, two angles of the one equal to two angles of the other, viz., the angle FAD to the angle FB C, and the angle AD F to the angle BCF; and the side AF of the... | |
| Euclides - Geometry - 1841 - 378 pages
...15. 1. angle EBC: and the angle AEG is equal* to the angle BEH; therefore the triangles AEG, BEH have two angles of the one equal to two angles of the other, each to each, and the sides AE, EB, adjacent to the equal angles, equal to one another: therefore their other * 28. 1.... | |
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