 | Edward Brooks - Arithmetic - 1877 - 528 pages
...OPERATION. 45 = 45 = 225 = 180 40+5 40+5 40X5+52 = 40*+40X5 2025 = 402+2(40x5)+5a FQ the square of 45 equals the square of the tens, plus twice the product of...the tens by the units, plus the square of the units, which we find to be 2025. SYNTHETIC SOLUTION. — Let the line AB represent a length of 40 units, and... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...will consist of two 10 x 2 = 20)125 figures. As we found in Involution 225 = the square of the tens, product of the tens by the units, plus the square of the units in its root, we must find the square of the tens in the first left-hand period of the power. The greatest... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...cube of the units. 3375= (10+ 5) X (10 + 5) X (10+ 5) = 15'. In this operation we see that the cube of a number consisting of tens and units is equal to the cube of the tens, plus three times the square of the tens multiplied by the units, plus three times... | |
 | Benjamin Greenleaf - Arithmetic - 1879 - 190 pages
...What is the square of 75 ? Of 85 ? 8. What is the square of 32 ? NOTE. — The square of any number is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. Thus, 32 is 3 tens and 2 units ; 3 tens, or 30, squared is 900 : twice 30 by 2 units is 120; the square... | |
 | William Frothingham Bradbury - Arithmetic - 1879 - 392 pages
...From this example it can be seen that the square of a numbeï whose figures are tens and units equals The square of the tens plus twice the product of the tens by the units plus the square of the units. 86. Find the square root of 576. OPERATION. As 576 consists of three figures, its 576 (24 Aus square... | |
 | Elias Loomis - Algebra - 1879 - 398 pages
...841 " 800+40+1. If, then, 841 is the square of a number composed of tens and units, it must contain the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. But these three terms are blended together in 841, and hence arises the peculiar difficulty in determining... | |
 | William Frothingham Bradbury - 1882 - 416 pages
...tens figure ' of the root must be 2. Now, as the number 576 equals the square of the tens of the root, plus twice the product of the tens by the units plus the square of the units, if we subtract from 576 the square of the tens of the root, that is 202, or 400, the remainder, 176,... | |
 | Benjamin Greenleaf - Algebra - 1879 - 350 pages
...a2, that is the square of 60, from the given number, we have the remainder 756, which must contain twice the product of the tens by the units, plus the square of the units, or 2 а6 -f- V. Dividing this remainder by 2 a, that is by 120, gives 6, which is the value oib. Then... | |
 | Joseph Ray - Arithmetic - 1880 - 420 pages
...first illustration. SECOND EXPLANATION. We learned in Art. 371 that the square of a number composed of tens and units is equal to the square of the tens,...the tens by the units, plus the square of the units. The square of (20 + 4), or 242, is 202 + 2 X (20 X 4) + 42. Now, if the square of the tens be taken... | |
 | George E. Seymour - Arithmetic - 1880 - 332 pages
...+ 2 (20X5) + (5)! 487. Hence, The square of any number consisting of tens and units is composed of the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. 488. From this general law it follows a. That if from the square of a number, the square of the tens... | |
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The square of a number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. 
