 | John Fair Stoddard - Arithmetic - 1868 - 428 pages
...the complete quotient. KOTE. — 1. If any partial dividend is less than the divisor, place a ciphet in the quotient and bring down the next figure of the dividend, thus forming the next partial dividend. 2. If any remainder is equal to, or greater than the divisor,... | |
 | John Homer French - Arithmetic - 1869 - 350 pages
...partial dividend. Hence, Whenever the partial dividend is less than ffico*D soumoxthe divisor, we place 0 in the quotient, and , , «» bring down the next figure of the dividend - [70S for a new partial dividend. " ' & 0 7 PROBLEMS. 45. How much does a man earn each month, whose... | |
 | George Payn Quackenbos - Arithmetic - 1869 - 348 pages
...increase the quotient • figure. 73 97. If the divisor will not go into the partial dividend, set 0 in the quotient, and bring down the next figure of the dividend. If several figures are brought down before the divisor will go into the partial dividend, set a naught... | |
 | Shelton Palmer Sanford - Arithmetic - 1872 - 404 pages
...figures of the dividend have been brought down. V. If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before. PROOF. The same as in SHORT DIVISION. NOTE 1. — When there is a remainder after... | |
 | George Payn Quackenbos - Arithmetic - 1872 - 350 pages
...increase the quotient ^ ^^ ngure. t " 97. If the divisor is not contained in the partial dividend, write 0 in the quotient, and bring down the next figure of the dividend. If several figures are brought down before the divisor is contained in the partial dividend, write... | |
 | Horatio Nelson Robinson, Daniel W. Fish - Arithmetic - 1873 - 384 pages
...multiply the divisor, 23, by tha ^' quotient figure, 2, and subtract the product, 46, from the part of tha dividend used, 'and to the remainder bring down the...the dividend, making a third partial dividend, 207 l 23 is contained in 207, 9 times ; multiplying and subtracting as before, nothing remains, and we... | |
 | Edward Olney - Arithmetic - 1875 - 338 pages
...time a remainder, with the next figure of the dividend annexed, will not contain the divisor, write 0 in the quotient, and bring down the next figure of the dividend. Reasons.—The reasons for this rule are the same as for the rule for Short Division, and instead of... | |
 | John Homer French - 1878 - 234 pages
...shown in the second solution. 82, Whenever the partial dividend i's lens than the divisor, we place 0 in the quotient and bring down the next figure of the dividend for a new partial dividend. PROBLEMS. 27. How many days will it take a cooper to make 2,718 barrels,... | |
 | Horatio Nelson Robinson, Daniel W. Fish - Arithmetic - 1879 - 374 pages
...dividend. We then multiply the divisor, 23, by the ' quotient figure, 2, and subtract the product, 46, from the part of the dividend used, and to the remainder...a third partial dividend, 207 ; 23 is contained in S07, 9 times ; multiplying and subtracting as before, nothing remains, and the entire quotient is 209.... | |
 | Edward Olney - Arithmetic - 1879 - 392 pages
...time a remainder, with the next figure of the dividend annexed, will not contain the divisor, write 0 in the quotient, and bring down the next figure of the dividend. REASONS. — The reasons for this rule are the same as for the rule for Short Division; and, instead... | |
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If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before. 
