 | Benjamin Greenleaf - 1851 - 332 pages
...the sum of the several parts of Fig. 4. Thus, 8000 + 7200 42160 4- 216 = 17576. Hence the following RULE. — 1. Separate the given number into periods of three figures each, by placing a point over the unit figure, and every third figure beyond the place of units. 2. Find... | |
 | Arithmetic - 1852 - 202 pages
...the finding of such a number, as, being multiplied into its square, will produce the number proposed. RULE. 1. Separate the given number into periods of...beginning at the units place. 2. Find the greatest cube contained in the left hand period, and set its root on the right of the given num|ber: subtract... | |
 | Ezra S. Winslow - Business mathematics - 1853 - 264 pages
...28561 ( 169. Ans. 1 26 ) 185 156 20605 ) 120000 329 ) 2961 103025 2961 16975 TO EXTRACT THE CUBE ROOT. RULE — 1. Separate the given number into periods of three figures each, by placing a point over the first, fourth,seventh,&c., counting from right to left — the root will... | |
 | Benjamin Greenleaf - 1854 - 342 pages
...the sum of the several parts of Fig. 4. Thus, 8000 + 7200 42160 + 216 = 17576. Hence the following RULE. — 1. Separate the given number into periods of three figures each, by placing a point over the unit figure, and every third figure beyond the place of units. 2. Find... | |
 | Elias Loomis - Algebra - 1855 - 356 pages
...divisor =1389 (284.) Hence, for the extraction of the cube root of numbers, we derive the following RULE. » . 1 . Separate the given number into periods of three figures each, beginning at the right hand. 2. Find the greatest cube contained in the left-hand period ; its ronl is the first figure... | |
 | Charles Guilford Burnham - 1857 - 342 pages
...those sides. From the foregoing example and illustration we derive the folio wins RULE. I. Distinguish the given number into periods of three figures each, beginning at the right hand. II. Find the greatest cube in the left-hand period, and place its root as a quotient in... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...at the right. Hence, for the extraction of the cube root of numbers, we have the following RULE. I. Separate the given number into periods of three figures each, beginning at the right hand ; the left hand period will often contain lem than three places of figures. II. Seek the... | |
 | Charles Davies - Arithmetic - 1861 - 496 pages
...number. Hence, the cube root of 4096 is 16. 389. Hence, to find the cube root of a number: Rule. — I. Separate the given number into periods of three figures each, beginning at the right, by placing a dot over the place of units, a second over the place of thousands, and so on over... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...divisor =1389 4167 (284.) Hence, for the extraction of the cube root of numbers, we derive the following RULE. 1. Separate the given number into periods of three figures each, beginning at the right hand. -v from the first period, and to the remainder bring down the second period for a dividend.... | |
 | Charles Davies - Arithmetic - 1865 - 468 pages
...number. Hence, the cube root of 4096 is 16. 389. Hence, to find the cube root of a number: Rule. — I. Separate the given number into periods of three figures each, beginning at the right, by placing a dot over the place of units, a second over the place of thousands, and so on over... | |
| |
RULE. 1. Separate the given number into periods of three figures each, beginning at the units place. 
