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" And because the angle ABC is equal to the angle BCD, and the angle CBD to the angle ACB... "
The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ... - Page 30
by Euclid - 1835 - 513 pages
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Annual Calendar of McGill College and University

McGill University - 1883 - 404 pages
...the sides also which subtend, or are opposite to, the equal angles, shall be equal to one another. 3. The opposite sides and angles of a parallelogram are equal to one another, and the diameter bisects the parallelogram, that is. aiviaes it into two equal parts. 4. Through the...
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Special Reports on Educational Subjects, Volumes 26-27

Great Britain. Board of Education - Education - 1912 - 1044 pages
...to the sum of an angle of an equilateral triangle and an angle of & regular pentagon. 3. Prove that the opposite sides and angles of a parallelogram are equal to one another. Find two points in two given straight lines which are not parallel, such that the line joining them...
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The Teaching of Mathematics in the United Kingdom

Great Britain. Board of Education - Mathematics - 1912 - 632 pages
...to the sum of an angle of an equilateral triangle and an angle of a regular pentagon. 3. Prove that the opposite sides and angles of a parallelogram are equal to one another. Find two points in two given straight lines which are not parallel, such that the line joining them...
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A Complete Epitome of Practical Navigation, and Nautical Astronomy ..., Volume 1

John William Norie, J. W. Saul - Nautical astronomy - 1917 - 642 pages
...whole angle ABD is equal to the whole angle ACD ; and the angle BAG has been shown to be equal to BDC ; therefore the opposite sides and angles of a parallelogram are equal to one another. Also the diameter BC bisects it. For since AB is equal to CD, and BC common, the two sides, AB, BC, are...
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Report of the Examinations Conducted by the Council of Higher Education ...

Newfoundland Council of Higher Education - 1917 - 184 pages
...is equal to the sum of the squares on QR and ST. Answer either 5 a or 5 b, not both. 5 a. Show that opposite sides and angles of a parallelogram are equal to one another, and that each diagonal bisects the parallelogram. Prove also that these diagonals bisect one another....
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Annual Report

Saskatchewan. Department of Education - Education - 1910 - 260 pages
...quadrilateral ABCD bisect the angles at A and C, prove that it is at right angles to the other diagonal. 5. (a) The opposite sides, and angles, of a parallelogram are equal to one another, and the diagonal bisects the parallelogram, that is, divides it into two equal parts. I. 34. (6) The...
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The Sheet-Metal Worker's Instructor

R. H. Warn, John G. Horner - Crafts & Hobbies - 2002 - 292 pages
...two parallel straight lines, it makes the alternate angles equal to one another. (Euc. I. 29.) (e) The opposite sides and angles of a parallelogram are equal to one another. (Euc. I. 34.) (/) Triangles upon the same base, or on equal bases, and between the same parallels,...
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Examinations Papers

1879 - 636 pages
...and AC is greater than the sum of DB and DC, and that the angle BDC is greater than the angle BAG. 3. The opposite sides and angles of a parallelogram are equal to one another. 4. The square on the hypothenuse of a right-angled triangle is equal to the sum of the squares on the...
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Annual Report of the Public Schools of the Province of British Columbia

British Columbia. Superintendent of Education - 1893 - 812 pages
...sector of a circle, and regular polygon, (b.) What two kinds of triangles have only two acute angles? 2. The opposite sides and angles of a parallelogram are equal to one another, and the diagonal bisects the parallelogram, that is, divides it into two equal parts. 3. (a.) Shew...
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Calendar

University of St. Andrews - 1900 - 670 pages
...that am — = a'"-n, where m and u are positive integers and m is greater (I than n. C. 14. Prove that the opposite sides and angles of a parallelogram are equal to one another, and that the diagonal bisects the parallelogram. The diagonals of a quadrilateral figure bisect each...
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