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" Two triangles are equal if two sides and the included angle of the one are equal respectively to two sides and the included angle of the other (sas = sas). Hyp. In A ABC and A'B'C', AB = A'B', BC = B'C', and Z B = Z B'. "
The Elements of Solid Geometry - Page 94
by William C. Bartol - 1893 - 95 pages
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Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...divides the figure into two equal triangles. PROPOSITION III. THEOREM 72. Two triangles are equal if two sides and the included angle of the one are equal respectively to two sides and the included angle of the other (sas = sas). Hyp. In A ABC and A'B'C', AB = A'B', BC = B'C', and ZB = Z B'. To prove A...
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Plane Geometry

Arthur Schultze - 1901 - 260 pages
...divides the figure into two equal triangles. PROPOSITION III. THEOREM 72. Two triangles are equal if two sides and the included angle of the one are equal respectively to two sides and the included angle of the other (sas = sas). Hyp. In A ABC and A'B'C', AB = A'B', BC = B'C', and Z B = Z B'. To prove...
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Plane and Solid Geometry

Arthur Schultze - 1901 - 392 pages
...divides the figure into two equal triangles. PROPOSITION III. THEOREM 72. Two triangles are equal if two sides and the included angle of the one are equal respectively to two sides and the included angle of the other (sas = sa-s.), Hyp. In A ABC and A'B'C', AB = A'B', BC=B'C', and ZB To prove AABC = AA'B'...
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Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...given line, two equal triangles are formed. PROPOSITION III. THEOREM 72. Two triangles are equal if two sides and the included angle of the one are equal respectively to two sides and the included angle of the other (sas = sas). B OB' ~ C' Hyp. In A ABC and A'B'C', AB = A'B', BC = B'C', and ZB = Z B',...
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Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...divides the figure into two equal triangles. PROPOSITION III. THEOREM 72. Two triangles are equal if two sides and the included angle of the one are equal respectively to two swfes <m<i tke included anrjte of the other (sas = sas). B OB' C' Hyp. In A ABC and A'B'C', AB=A'B',...
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Elementary Geometry, Plane and Solid: For Use in High Schools and Academies

Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...equal, respectively, to the base and the two adjacent angles of the other, CONCLUSION. Then the two sides and the included angle of the one are equal, respectively, to the two sides and the included angle of the other. Stated in this way, the hypothesis in Proposition...
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Solid Geometry, Volumes 6-9

George Albert Wentworth - Geometry, Solid - 1902 - 246 pages
...respectively, to a leg and the homologous acute angle of the other. 143. Two triangles are equal if two sides and the included angle of the one are equal, respectively, to two sides and the included angle of the other. 144. Two right triangles are equal if their legs are equal, each to each. 145. In an...
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Plane and Solid Geometry

James Howard Gore - Geometry - 1902 - 266 pages
...triangle. DB + DA + DC>l(AB + BC + AC). PBOPOSITION XIII. THEOREM. 86. Two triangles are equal each to each when two sides and the included angle of the one are equal respectively to tivo sides and the included angle of the other. C C< B A' In the triangles ABC and A'B'O', let AB =...
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Plane and Solid Geometry

George Albert Wentworth - Geometry - 1904 - 496 pages
...Iden. and Z BAD = Z CAD. Const. .-. AADB = A AZX7, §143 are equal if two sides and the included Z of the one are equal, respectively, to two sides and the included Z of the other). (being homologous angles of equal triangles). §128 QED 146. COR. An equilateral triangle...
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School Science and Mathematics, Volume 17

Education - 1917 - 906 pages
...thought. The student is, as a rule, not much surprised to find that two plane triangles are congruent when two sides and the included angle of the one are equal, respectively, to the corresponding parts of the other. On the other hand we really open up broad and surprising vistas...
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